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3 years ago

11

Me need help the 5 is not a part of the question

2 answers:

snow_lady [41]3 years ago

8 0

Box 1 : -12a Box 2: 8B box 3: -12a

ikadub [295]3 years ago

5 0

Answer:

-12a, 8B, 12a

Step-by-step explanation:

hope it helps

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Help please thanks :))))))))))))))))

shtirl [24]

The answer is 1. Yeah

5 0

3 years ago

Read 2 more answers

Simplify the polynomial by combining like terms

Veseljchak [2.6K]

Answer:

22 x^2

Step-by-step explanation:

Simplify the following:

11 x^2 + 11 x^2

Hint: | Add like terms in 11 x^2 + 11 x^2.

11 x^2 + 11 x^2 = 22 x^2:

Answer: 22 x^2

none of your answers are correct.

8 0

3 years ago

a trail mix recipe calls for 3/4 a cup of raisins for every 5/8 of a cup of peanuts. how mant peanuts will be needed for 1 cup o

xxTIMURxx [149]

Answer:

5/6 rup of raisins?

Step-by-step explanation

Sorry if that is wrong

4 0

3 years ago

How many solutions does this system of equations have?

azamat

Answer:

its one solution

Step-by-step explanation:

3 0

3 years ago

Find the volume of a trough 5 meters long whose ends are equilateral triangles, each of whose

yawa3891 [41]

Answer:

$V=5\sqrt{3}\ m^3$

Step-by-step explanation:

we know that

The volume of a trough is equal to

$V=BL$

where

B is the area of equilateral triangle

L is the length of a trough

step 1

Find the area of equilateral triangle B

The area of a equilateral triangle applying the law of sines is equal to

$B=\frac{1}{2} b^{2} sin(60\°)$

where

$b=2\ m$

$sin(60\°)=\frac{\sqrt{3}}{2}$

substitute

$B=\frac{1}{2}(2)^{2} (\frac{\sqrt{3}}{2})$

$B=\sqrt{3}\ m^{2}$

step 2

Find the volume of a trough

$V=BL$

we have

$B=\sqrt{3}\ m^{2}$

$L=5\ m$

substitute

$V=(\sqrt{3})(5)$

$V=5\sqrt{3}\ m^3$

3 0

4 years ago