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emmainna [20.7K]
3 years ago
11

Why is it not possible to form a right triangle with the lengths 2, 4 and 7?

Mathematics
2 answers:
Anna [14]3 years ago
7 0

Step-by-step explanation:

answer is

B. because 2 + 4 = 7

please mark as brilliant

Korolek [52]3 years ago
5 0

Answer:

Pythagorean Theorem

a^2 + b^2 = c^2

2^2 + 4^2 = 7^2?

This is not true, so the answer is C. Because 2² + 4² ≠ 7².

Let me know if this helps!

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ticket sales for a local concert totaled $101,244 yesterday. After the ticket window closed today, the cashiers counted 968 tick
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The cost of one concert ticket is approximately  $148.59.

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3 0
2 years ago
Use the divergence theorem to find the outward flux of the vector field F(x,y,z)=2x2i+5y2j+3z2k across the boundary of the recta
aksik [14]

Answer:

The answer is "120".

Step-by-step explanation:

Given values:

F(x,y,z)=2x^2i+5y^2j+3z^2k \\

differentiate the above value:

div F =2 \frac{x^2i}{\partial x}+5 \frac{y^2j}{\partial y}+3 \frac{z^2k }{\partial z}  \\

        = 4x+10y+6z

\ flu \ of \ x = \int  \int div F dx

              = \int\limits^1_0 \int\limits^3_0 \int\limits^1_0 {(4x+10y+6z)} \, dx \, dy \, dz \\\\ = \int\limits^1_0 \int\limits^3_0 {(4xz+10yz+6z^2)}^{1}_{0} \, dx \, dy  \\\\ = \int\limits^1_0 \int\limits^3_0 {(4x+10y+6)} \, dx \, dy  \\\\ = \int\limits^1_0  {(4xy+10y^2+6y)}^3_{0} \, dx   \\\\ = \int\limits^1_0  {(12x+90+18)}\, dx   \\\\= {(12x^2+90x+18x)}^{1}_{0}   \\\\= {(12+90+18)}   \\\\=30+90\\\\= 120

6 0
3 years ago
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