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tangare [24]
3 years ago
6

How do you solve x2 + 6x = 135

Mathematics
2 answers:
aev [14]3 years ago
7 0

Answer:

the answer is b on edge

Step-by-step explanation:

Arte-miy333 [17]3 years ago
6 0

Answer:

-15 and 9

Step-by-step explanation:

x^2+6x=135 \\\\\\x^2+6x-135=0 \\\\\\x=\dfrac{-6\pm\sqrt{36+540}}{2}=\dfrac{-6\pm\sqrt{576}}{2}=\dfrac{-6\pm24}{2}=-3\pm12=-15,9

Hope this helps!

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Como calcular el 15% de 300
ArbitrLikvidat [17]
300 x .15 y te dará la respuesta
4 0
2 years ago
Aaron has 7/8 gallon of bottled water.How many 3/6 gallon servings can he pour
Anettt [7]
7/8 + 3/6 = 10/14 = 5/7 = 0.71 And if you want to make it a whole number, you multiply by 100 and you should get 71 as a whole number. Therefore: he can pour 71 gallon servings of bottled water. I hope this is helpful!!^_^!!
6 0
3 years ago
Graph ARST with vertices R(6, 6), S(3, -6), and T(0, 3) and its image after a
padilas [110]

Answer:

The answer is the second figure and the vertices of Δ R'S'T' are:

R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

Step-by-step explanation:

* Lets revise some transformation

- If point (x , y) reflected across the x-axis

 ∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

 ∴ Its image is (-x , y)

- If point (x , y) reflected across the line y = x

 ∴ Its image is (y , x)

- If point (x , y) reflected across the line y = -x

 ∴ Its image is (-y , -x)

- Now we can solve the problem

∵ R = (6 , 6) , S = (3 , -6) , T = (0 , 3), they are the vertices of ΔRST

- The triangle RST is reflected over the y-axis

- According to the rule above the signs of x-coordinates will change

∵ R = (6 , 6)

∴ Its image is (-6 , 6)

∵ S = (3 , -6)

∴ Its image is (-3 , -6)

∵ T = (0 , 3)

∴ Its image is (0 , 3)

* Now lets look to the figure to find the correct answers

- The image of Δ RST is ΔR'S'T'

∵ The vertices of the image of ΔRST are:

  R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

* The answer is the second figure

7 0
3 years ago
J= -8c^2 - 4cd - d^2 k= -3c^2 +7cd - 3d^2 j+k =
irina [24]
J=-8c²-4cd-d²
k=-3c²+7cd-3d²
j+k=
-8c²-4cd-d²-3c²+7cd-3d²
-11c²-4d²+3cd
6 0
4 years ago
Which function has the following characteristics?
iren [92.7K]

Using the asymptote concept, the function with a vertical asymptote at x = 3 and an horizontal asymptote at y = -\frac{1}{2} is given by:

f(x) = -\frac{x}{2(x - 3)}

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

The vertical asymptote at x = 3 means that x = 3 is a root of the denominator, hence:

f(x) = \frac{g(x)}{x - 3}

The horizontal asymptote at y = -1/2 means that:

\lim_{x \rightarrow \infty} f(x) = -\frac{1}{2}

Which happens if g(x) = -\frac{x}{2}, hence the function is:

f(x) = -\frac{x}{2(x - 3)}

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

4 0
2 years ago
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