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bogdanovich [222]
3 years ago
13

a bell tolls every 10 minutes. another bell tolls every 15 minutes. both bells toll at 6:00pm. they will toll together at what t

ime
Mathematics
2 answers:
lidiya [134]3 years ago
8 0
The answer is 6:30 pm
Ne4ueva [31]3 years ago
4 0
Basically, we need to find the lowest common multiple of 10 and 15.

that multiply would be 30. That means that the bells will ring together in 30 minutes.
So 30 minutes from 6 p.m. is 6:30 p.m. <==
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4 x 6 - 8 / 4 = help me out
nydimaria [60]

Answer:

22

Step-by-step explanation:

You use the order of operations: PEMDAS.

Sooo...

4*6-8/4=

24-8/4=

24-2=

22

4 0
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Solve 2(3a² - 1) - 6a = 5a {-1/2, 2/3} {-1/6, 2} {}
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The GCF of 36 and 63 is
Vitek1552 [10]

Answer:

9

Step-by-step explanation:

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3 years ago
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Find the area of each figure. Round to the nearest tenth if necessary
iren [92.7K]
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8 0
2 years ago
17) The coordinates of quadrilateral EFGH are E(7, 7), F(4, 8), G(2, 2), H(7, 2). Show that EF is perpendicular to FG.
strojnjashka [21]

Answer:

see explanation

Step-by-step explanation:

first we calculate the slopes of EF and FG using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ = E (7, 7 ) and F (4, 8 )

m_{EF} = \frac{8-7}{4-7} = \frac{1}{-3} = - \frac{1}{3}

repeat with (x₁, y₁ ) = F (4, 8 ) and (x₂, y₂ ) = G (2, 2 )

m_{FG} = \frac{2-8}{2-4} = \frac{-6}{-2} = 3

if 2 lines are perpendicular then the product of their slopes = - 1

here

m_{EF} × m_{FG} = - \frac{1}{3} × 3 = - 1

then EF is perpendicular to FG

3 0
2 years ago
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