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zvonat [6]
3 years ago
7

Tyler earned $364.80 at his job when he worked for 16 hours. How much money did he earn each hour?

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
5 0

Answer: $22.80/hour

Step-by-step explanation: 364.80 : 16 = 22.80

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Lntegers 0, -2, -3, -4, -5, -6, -7, -8, and -10 to fill in a 3 x 3 magic square so that every row, column, and diagonal has the
kramer

The given numbers are 0, -2, -3, -4, -5, -6, -7, -8, and -10.

Sum of all the integers is -45.

There are 9 places in 3x3 magic square, so divide -45 by 9, we have -45/9=-5.

Put the number -5 at the center place in the magic square.

Now, take the integer having the largest magnitude, i.e -10.

There are two positions to place -10, one is diagonal positions and the other is non-diagonal positions and to make sum = -15, the other number with -5 and -10 must be 0 as shown in the figure (i) and (ii).

Now, the row and column having 0 must have -8 and -7 to make sum -15, which disregards the possibility of -10 at the diagonal place ( figure (i)). So, proceeds with the places in figure (ii), the possible places of -8 and -7 have been shown in figure (iii).

Now, as the sum of diagonals = -15, so place -3 and -2 at diagonal positions and also place the remaining numbers -4 and -6 to make the sum of numbers in columns and rows -15 as shown in figure (iv).

3 0
2 years ago
What is the solution to this equation? <br> 2x+10=28
Strike441 [17]

Answer:

x=9

Step-by-step explanation:

2x+10=28

Subtract 10 from both sides

2x=18

Divide by 2 on both sides

x=9

5 0
3 years ago
Read 2 more answers
What is the y-intercept of the line?
gregori [183]

Answer:

28

Step-by-step explanation:

3 0
3 years ago
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Write the function 3x2 -12x + 61 in<br> vertex form.
Scilla [17]

Answer:

y=3(x-2)²+49

Step-by-step explanation:

vertex-form is given as y=a(x-h)²+k, where (h,k) is the coordinate of the vertex

we are given the function in standard form, which is:

y=ax²+bx+c

our function is:

3x²-12x+61

the value of a is given as the value of the coefficient in front of the squared term (in this case, it's 3)

here's the function so far in vertex form:

y=3(x-h)²-k

now, we need to find the vertex

to find h, we can use the formula (-b/2a)

the value of b is given as the value of the coefficient in front of the linear term (in this case, it's -12)

and we know from above that a=3

substitute what we know into the formula:

h=-b/2a

h=12/2(3)

h=12/6

h=2

so h is 2

*Please note that when we substitute it into the function, it's -2

so here is our function so far:

y=3(x-2)²-k

now to find k, which is given in the formula c-(b²/4a)

we know from above that a=3, b=-12

c is the value of the constant (term without a variable). In this case, it's 61

once again, substitute what we know into the equation:

k=61-((-12)²/4(3))

k=61-(144/12)

k=61-12

k=49

therefore the function will be:

y=3(x-2)²+49

Hope this helps!

6 0
2 years ago
Quaddlateral CART is dilated with the center at the origin and a scale
Zanzabum

Answer:

Step-by-step explanation:

Rule for the dilation of a point by a scale factor 'k' about the origin is,

(x, y) → (kx, ky)

If the scale factor for the dilation is k=\frac{6}{5},

Rule for the dilation,

A(x, y) → A'(\frac{6}{5}x,\frac{6}{5}y)

If the coordinates of point A' (Image) is given and we have to find the coordinates of point A (Preimage),

Rule for the dilation,

A'(x, y) → A(\frac{5}{6}x,\frac{5}{6}y)

             Quadrilateral CART                   Quadrilateral C'A'R'T'

                          (x, y)                                           (\frac{6}{5}x,\frac{6}{5}y)

                       C(-5, 15)                                       C'(-6, 18)

                       A(10, 5)                                         A'(12, 6)

                       R(-20, -10)                                    R'(-24, -12)                          

                       T(-25, 0)                                       T'(-30, 0)

8 0
3 years ago
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