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denpristay [2]
2 years ago
13

HELP ASAP

Mathematics
1 answer:
Darina [25.2K]2 years ago
4 0
I need the points sorry !!
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Can somebody please balance this !?!
Lera25 [3.4K]
\mathrm{CO}_2 has 2 oxygens for every carbon. \mathrm{CO} will contribute one of each for every molecule. You then have to have an even multiple of \mathrm{CO} molecules to not end up with an odd number of oxygens.

So if you take 2\mathrm{CO}, you should end up with 2 carbons on the RHS. 2\mathrm{CO}_2 then has 4 oxygens. 2 of them are already accounted for, so you just need one \mathrm O_2 to balance out the reaction.

1\mathrm O_2+2\mathrm{CO}\Rightarrow2\mathrm{CO}_2
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3 years ago
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irinina [24]
216/24=9
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2 years ago
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Naddik [55]
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3 years ago
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Trava [24]

Answer:

E)82

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