The absolute value function |<em>x</em>| always returns a non-negative number. It takes any number <em>x</em> and returns <em>x</em> if it's already non-negative, or -<em>x</em> if it is negative in order to make it positive.

For the equation
-3 + 4 |2<em>x</em> - 5| = 14
rearrange terms to get
|2<em>x</em> - 5| = 17/4
Now,
• if 2<em>x</em> - 5 ≥ 0, then |2<em>x</em> - 5| = 2<em>x</em> - 5. Then
2<em>x</em> - 5 = 17/4
• and if instead 2<em>x</em> - 5 < 0, then |2<em>x</em> - 5| = -(2<em>x</em> - 5), so that
-(2<em>x</em> - 5) = 17/4, or
2<em>x</em> - 5 = -17/4
In the first case,
2<em>x</em> - 5 = 17/4
2<em>x</em> = 17/4 + 5 = 37/4
<em>x</em> = 37/8
In the second case,
2<em>x</em> - 5 = -17/4
2<em>x</em> = -17/4 + 5 = 3/4
<em>x</em> = 3/8
the fiest answer is x=6 for the second one the answer is x=4
Step-by-step explanation:
x+15/5x+1 =15/35 then cross multiply
1st one
3x-y=6, in order to be able to graph this you would have to change the equation to y=, so you need to subtract 3x from that side making it -y=-3x+6, now you need to y positive, so divide both sides by -1, thus making the equation look like y=3x-6, now if you can't plug this into a calculator to see what it would look like then you need to know what y=mx+b means. y is the equation you want to graph obviously, m = the slope, so our slope in this case would be -3, and b = our y intercept, so it would be (0,-6), so plot (0,-6) and use the slope to plot the rest of the points, some other points in this line should include (2,0), (-1,-9) and (4,6), just to name a few. Hope this helps.
Answer:
x = 13
Step-by-step explanation:
call the missing number x
8 - x = - 5 Subtract 8 from both sides
8-8 - x = -5-8 Combine
-x = - 13 Multiply by -1
x = 13