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3 years ago

Which of the following expressions is equivalent to (8x)^2/3 ?

Mathematics

1 answer:

miv72 [106K]3 years ago

5 0

Answer:

Step-by-step explanation:

Given the expression (8x)^2/3

This can also be expressed as;

(8x)^2/3

= (2^3x)^2/3

= (2³)^2/3 * x^2/3

= 2^2 * x^2/3

= 4x^2/3

Hence the equivalent expression is 4x^2/3

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The length of an equilateral triangle is increased by 5 cm. The perimeter of the new triangle is 72 cm. What is the side length

Igoryamba

Answer:

19cm

Step-by-step explanation:

An equilateral triangle is a triangle where the length of the 3 sides are the same.

the perimeter is the sum of the 3 sides

for example, if the length of the side of the an equilateral triangle is 5, the perimeter is 5 x 3 = 15

let x = unknown length of side

length after increase = x + 5

(x + 5) x 3 = 72

divide both sides of the equation by 3

x + 5 = 24

subtract 5 from both sides of the equation

x = 24 - 5 = 19cm

6 0

3 years ago

7.3 as a mixed number simlified

joja [24]

Answer: 7 3/10
seven as a whole number, and .3 equals to 3/10 when converted

8 0

3 years ago

Six stand-up comics, A, B, C, D, E, and F, are to perform on a single evening at a comedy club. The order of performance is

kiruha [24]

Answer:

a) 1/6

b) 1/36

c) 1/720

d) 1/3

Step-by-step explanation:

a) Any of the six comics can perform in the fourth place, so there is one chance in six that Comic F is the one that performs fourth.

$P(F=4th)=1/6$

b) In this case, we have two conditions. Both are independent of each other, so the probability of both happening is the product of the probabilities of each happening individually:

$P(D=4th \&B=2nd)=P(D=4th)\cdot P(B=2nd)=(1/6)\cdot(1/6)=1/36$

c) This combination is one in all possible orders of perform. The amount of combinations of orders is n!=6!=720 possible combinations. So the probability of this specific order is:

$P(F, D, B, A, C, E)=1/720$

d) In this case, of the six possible comics performing in the last place, we calculate the probability of 2 of them being in that place. So the probability is:

$P(C=6th\,or\, E=6th)=2/6=1/3$