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2 years ago

Find the number of real- number solutions of the equation x^2+10=2

Mathematics

1 answer:

Andrew [12]2 years ago

4 0

Answer:

imaginary

Step-by-step explanation:

$x {}^{2} = 2 - 10 \\ {x}^{2} = - 8 \\ x = \sqrt{ - 8}$

from the working strp, we know that the number is imaginary

we can't square root the negative number

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1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

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Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

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$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

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$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

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$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

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