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lisabon 2012 [21]
2 years ago
10

Find the number of real- number solutions of the equation x^2+10=2

Mathematics
1 answer:
Andrew [12]2 years ago
4 0

Answer:

imaginary

Step-by-step explanation:

x {}^{2}  = 2 - 10 \\  {x}^{2}  =  - 8 \\ x =  \sqrt{ - 8}

from the working strp, we know that the number is imaginary

we can't square root the negative number

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Note:
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Answer for: -10 = 10 = 7m. m =<br><br> •0<br> •7 <br> •10<br> •11
wel

Answer:

Ok so your answer should be m = 0

Step-by-step explanation:

the explanation is to Rewrite the equation as  − 10 +7 m = − 10 .− 10 + 7 m = − 10

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to the right side of the equation.

7 m = 0

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and simplify.

m = 0

i hope this can help

5 0
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