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Flura [38]
4 years ago
7

5 less than twice a number is equal to one half the difference of three times the number and 13. Find the number.

Mathematics
1 answer:
antoniya [11.8K]4 years ago
6 0

Answer:

The number will be -3.

Step-by-step explanation:

Let us assume the number as x.

Given:

⇒ 5 less than twice a number that will be 2x - 5, which is equal to half the difference of three times the number and 13

We have to find the number.

Solution:

The difference of three times the number and 13 could be represented as : 3x - 13

The value be equal to \frac{1}{2} of this 3x - 13 ⇒ \frac{1}{2}  ( 3x - 13 )

As we can see here,

  • That we got a equation ⇒ 2x - 5 = \frac{1}{2}  ( 3x - 13 )

Now, we can solve the above equation:

2x - 5 = \frac{1}{2}  ( 3x - 13 )

We have multiply both sides by 2 ⇒ 4x - 10 = 3x - 13

then, ⇒ x - 10 = -13

   ⇒   x = -3  

Hence we can say that number which was assumed as x will be -3.

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Step-by-step explanation:

Given that

\int \int   Df(x,y)dA=\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy+\int_5^7\int_0^{7-y} f(x,y)dxdy\; \cdots (i)

For the term  \int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy.

Limits for x is from x=0 to x=\frac {2y}{5} and for y is from y=0 to y=5  and the region D, for this double integration is the shaded region as shown in graph 1.

Now, reverse the order of integration, first integrate with respect to y then with respect to x . So, the limits of y become from y=\frac{5x}{2} to y=5 and limits of x become from x=0 to x=2 as shown in graph 2.

So, on reversing the order of integration, this double integration can be written as

\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy=\int_0 ^2\int _ {\frac {5x}{2}}^5 f(x,y)dydx\; \cdots (ii)

Similarly, for the other term  \int_5 ^7\int _0 ^ {7-y} f(x,y)dxdy.

Limits for x is from x=0 to x=7-y and limits for y is from y=5 to y=7  and the region D, for this double integration is the shaded region as shown in graph 3.

Now, reverse the order of integration, first integrate with respect to y then with respect to x . So, the limits of y become from y=5 to y=7-x and limits of x become from x=0 to x=2 as shown in graph 4.

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\int_5 ^7\int _0 ^ {7-y} f(x,y)dxdy=\int_0 ^2\int _5 ^ {7-x} f(x,y)dydx\;\cdots (iii)

Hence, from equations (i), (ii) and (iii) , on reversing the order of integration, the required expression is

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\int_a^b\int_{g_1(x)}^{g_2(x)} f(x,y)dydx

We have,

a=0, b=2, g_1(x)=\frac{5x}{2} and g_2(x)=7-x.

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