Factor 22 + 13z + 12

What is 4 1/5 x 5/14

Bogdan [553]

4 1/5*5/14
4 1/5=21/5 since 4*5+1=21,
So 21/5*5/14=21/14 since the 5's cancel out,
simplify, you get 3/2.
Answer: 3/2.

5 0

3 years ago

Read 2 more answers

I NEEEEEEEED HEEEEEEEEEEEEELLLLLLLLLLLLLLLPPPPPPPPPPPPP PPPPPPPPPPPLLLLLLLLLLLLLLLLZZZZZZZZZZZZZ

Serga [27]

Answer:

Hey! I have two answers for you. If x is next to the denominator of 7 then its −1/35 but if x is next to the whole fraction then its just -35

Step-by-step explanation:

4 0

3 years ago

Simplify 4 (x3 – 3y2) – 2 (3x3 – 5y2)

Phoenix [80]

$\huge \bold{answer}$

5 0

3 years ago

Two automobiles left simultaneously from cities A and B heading towards each other and met in 5 hours. The speed of the automobi

quester [9]

Answer:

450 km

Step-by-step explanation:

Equations

We can define 3 variables: a, b, d. Let "a" and "b" represent the speeds of the cars leaving cities A and B, respectively. Let "d" represent the distance between the two cities. We can write three equations in these three variables:

1. The relation between "a" and "b":

a = b -10 . . . . . . . the speed of car A is 10 kph less than that of car B

2. The relation between speed and distance when the cars leave at the same time:

d = (a +b)·5 . . . . . . distance = speed × time

3. Note that the time it takes car B to travel 150 km to the meeting point is (150/b). (time = distance/speed) The total distance covered is ...

distance covered by car A in 4 1/2 hours + distance covered by both cars (after car B leaves) = total distance

4.5a + (150/b)(a +b) = d

__

Solution

Substituting for d, we have ...

4.5a + 150/b(a +b) = 5(a +b)

4.5ab +150a +150b = 5ab +5b^2 . . . . . . multiply by b, eliminate parentheses

5b^2 +0.5ab -150(a +b) = 0 . . . . . . . . . . subtract the left side

Now, we can substitute for "a" and solve for b.

5b^2 + 0.5b(b-10) -150(b -10 +b) = 0

5.5b^2 -5b -300b +1500 = 0 . . . . . . . . eliminate parentheses

11b^2 -610b +3000 = 0 . . . . . . . . . . . . . multiply by 2

(11b -60)(b -50) = 0 . . . . . . . . . . . . . . . . factor

The solutions to this equation are ...

b = 60/11 = 5 5/11 . . . and . . . b = 50

Since b must be greater than 10, the first solution is extraneous, and the values of the variables are ...

b = 50
a = b-10 = 40
d = 5(a+b) = 5(90) = 450

The distance between A and B is 450 km.

_____

Check

When the cars leave at the same time, their speed of closure is the sum of their speeds. They will cover 450 km in ...

(450 km)/(40 km/h +50 km/h) = 450/90 h = 5 h

__

When car A leaves 4 1/2 hours early, it covers a distance of ...

(4.5 h)(40 km/h) = 180 km

before car B leaves. The distance remaining to be covered is ...

450 km - 180 km = 270 km

When car B leaves, the two cars are closing at (40 +50) km/h = 90 km/h, so will cover that 270 km in ...

(270 km)/(90 km/h) = 3 h

In that time, car B has traveled (3 h)(50 km/h) = 150 km away from city B, as required.

5 0

4 years ago

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If g is a differentiable function such that g(x)<0 for all real numbers x and if f'(x) = (x2 - 4)g(x), which of the following

galina1969 [7]

We want to see what can we say about f(x) extremes for the given information. We will see that the correct option is:

V: f has a relative minimum at x=-2 and a relative maximum at x=2.

<h3>Maximums and minimums.</h3>

A given function f(x) will have a maximum/minimum at x₀ if:

f'(x₀) = 0

It will be a maximum if f''(x₀) < 0
It will be a minimum if f''(x₀) > 0.

Here we do know that:

f'(x) = (x^2 - 4)*g(x)
g(x) < 0 for all numbers x.

Then the only zeros of f'(x) are when (x^2 - 4) = 0.

And this happens for x = 2 and x = -2

Now let's see if these are minimums or maximums, we have:

f''(x) = 2*x*g(x) + (x^2 - 4)*g'(x)

If we evaluate this in x = 2, we get:

f''(2) = 2*2*g(2) + (2^2 - 4)*g'(2)

= 4*g(2) + 0*g'(2) = 4*g(2)

And g(x) is always negative, then 4*g(2) < 0, then:

f''(2) < 0

Meaning that in x = 2 we have a relative maximum.

For x = -2 we have:

f''(-2) = 2*-2*g(-2) + ((-2)^2 - 4)*g'(-2)

= -4*g(2) > 0

Then f''(-2) > 0, meaning that in x = -2 we have a relative minimum.

Then the correct option is:

V: f has a relative minimum at x=-2 and a relative maximum at x=2.

If you want to learn more about maximums and minimums, you can read:

brainly.com/question/1938915

6 0

3 years ago