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3 years ago

Which triangles are congruent? How do you know?

Mathematics

2 answers:

NARA [144]3 years ago

6 0

C and D lengths is of 3 and heights of 4, so they are congruent

choli [55]3 years ago

3 0

Use the side lengths! C and D have lengths of 3 and heights of 4.
Also use how far away they are from the axis.

Both C and D are 2 away from each axis on the end point.
This also goes with A.
However, B does not seem to be congruent in the sense of (coordinates)
It is the same length and height.

You might be interested in

A charity receives 2025 contributions. Contributions are assumed to be mutually independent and identically distributed with mea

uysha [10]

Answer:

The 90th percentile for the distribution of the total contributions is $6,342,525.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums of size n, the mean is $\mu*n$ and the standard deviation is $s = \sqrt{n}*\sigma$

In this question:

$n = 2025, \mu = 3125*2025 = 6328125, \sigma = \sqrt{2025}*250 = 11250$

The 90th percentile for the distribution of the total contributions

This is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. Then

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$1.28 = \frac{X - 6328125}{11250}$

$X - 6328125 = 1.28*11250$

$X = 6342525$

The 90th percentile for the distribution of the total contributions is $6,342,525.

3 0

3 years ago

Use the quadratic formula to solve. Round to the nearest tenth if necessary.<br> 2x^2 -3x -7 = 0

abruzzese [7]

The quadratic formula is:

$\frac{-b + \sqrt{b^2 - 4ac} }{2a}$ and $\frac{-b - \sqrt{b^2 - 4ac} }{2a}$

In this case, a = 2, b = -3, and c = -7

So, we can plug in the numbers to get:

$\frac{-(-3) + \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)}$ and $\frac{-(-3) - \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)}$

Simplifying, we get:

$\frac{3 + \sqrt{65} }{4}$ and $\frac{3 - \sqrt{65} }{4}$

You need to use a calculator to find what these would be in decimal form. The answer, rounded to the nearest tenth, is: x = 2.8, x = -1.3

8 0

2 years ago

The product of 3p and q - 3.

shusha [124]

The product of 3p and q-3 would be put in to equation form like this: 3p(q-3)

To find your answer. You have to distribute the 3p to by individually multiplying it by q and -3

It should now look like this: $3pq -9p$

So your answer is: $3pq -9p$

8 0

3 years ago

Suppose that 13 inches of wire costs 52 cents. At the same rate, how many inches of wire can be bought for 32 cents?

kirill115 [55]

Answer:

So we have a ratio which you have specified 13:52. So we just need to get the same ratio for 13. 32/52 is how we get 32 from multiplying by 52. So now we just need to multiply it for 13 also'

13*32/52 = 8. Therefore the answer to this is 8

<h2 /><h2><u>8 is answer</u></h2>

8 0

3 years ago

Slove system of equations y=2x-3 y=x^2-2x-8

Fiesta28 [93]

Answer:

2 solutions:

x=5 and y=7

x=-1 and y=-5

Step-by-step explanation:

y=2x-3

y=x^2-2x-8

y=y so:

2x-3=x^2-2x-8

simplifying to:

x^2-4x-5=0

factoring to:

(x-5)(x+1)=0

x=5 or x=-1

if x=5 then y=2(5)-3=7

if x=-1 then y=2(-1)-3=-5

3 0

2 years ago