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Maksim231197 [3]
3 years ago
11

Find the numbers a, b and c if the polynomial x3−18x2+24xb−c is the cube of the binomial x+2a.

Mathematics
1 answer:
mojhsa [17]3 years ago
6 0

Answer:

a=-3\\ \\b=\dfrac{9}{2}\\ \\c=216

Step-by-step explanation:

Use formula

(u+v)^3=u^3+3u^2v+3uv^2+v^3.

Hence,

(x+2a)^3=x^3+3x^2\cdot 2a+3x\cdot (2a)^2+(2a)^3=x^3+6ax^2+12a^2x+8a^3.

This expression is equal to

x^3-18x^2+24bx-c,

so we can equate the coefficients at powers of x:

x^3:\ 1=1\\ \\x^2:\ 6a=-18\Rightarrow a=-3\\ \\x:\ 12a^2=24b\Rightarrow b=\dfrac{9}{2}\\ \\1=x^0:\ 8a^3=-c\Rightarrow c=-8\cdot (-3)^3=216.

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