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klio [65]
2 years ago
8

So so sorry, but i have another one~ in this, the numbers can be used only once

Mathematics
2 answers:
anzhelika [568]2 years ago
8 0
What do you mean you can’t use the number twice?
Aliun [14]2 years ago
6 0

Answer:

1 + 2 + 3 + 4 + 5 + 9=24

10 + 9 + 8 + 2 + 1 + 6=36

Step-by-step explanation:

When you mean you can only use the numbers once do you mean you can't use it twice on the same one or you can't use the number after you have used it on one of them?  

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5/6k=-20 what is the correct answer ??
damaskus [11]
<span>5/6k=-20

k=-24

Hope this helps
</span>
4 0
3 years ago
Read 2 more answers
Please help with this
12345 [234]
The answers would be: B, D, and E
4 0
3 years ago
Show work/pls explain
Tamiku [17]
9+6(2^2+4)
9+6(4+4)
9+(6)(8)
9+48
=57
5 0
3 years ago
Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
An airplane captain must have a minimum of 1500 hours of<br> flying experience. Tom has 715.
MatroZZZ [7]

Answer:

He needs 785 more minutes

Step-by-step explanation:

8 0
2 years ago
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