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marta [7]
4 years ago
6

What is the discriminant D of the equation? a2−2a+5=0 Enter your answer in the box.

Mathematics
2 answers:
kirill115 [55]4 years ago
7 0
The Discriminant:
D = b² - 4 a c
D = (-2)² - 4 · 1 · 5 = 4 - 20 = - 16
D = - 16 
D < 0 ,  which means that there are no real solutions. The solutions of this equation are complex conjugate numbers.
xxMikexx [17]4 years ago
6 0
For a quadratic equation ax^2 + bx + c = 0, the discriminant is given by b^2 - 4ac
Thus for a^2 - 2a + 5 = 0,
a = 1, b = -2 and c = 5
b^2 - 4ac = (-2)^2 - 4(1)(5) = 4 - 20 = -16
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Factor completely<br> -2x^4+6x^3+8x^2
vlada-n [284]

Answer:

-2x²(x + 1)(x - 4)

Step-by-step explanation:

Hello!

Factor:

  • -2x^4 + 6x^3 + 8x^2
  • -2x^2(x^2 - 3x - 4)        Take out GCF

Think: What numbers add up to -3 and multiply to -4?

Answer: -4 and 1

Continue:

  • -2x^2(x^2 - 3x - 4)
  • -2x^2(x^2 - 4x + x - 4)
  • -2x^2(x(x - 4) + 1(x - 4))       Factor by Grouping
  • -2x^2(x + 1)(x - 4)

The complete factored form is -2x²(x + 1)(x - 4)

5 0
2 years ago
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inysia [295]
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4 0
3 years ago
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For tall heterozygotes with antennae, the offspring are:
Misha Larkins [42]

Recombinant frequency between T and A is 12%

<u>Explanation:</u>

<u></u>

Two characters are considered - height and antennae

Traits of height - Tall and Dwarf

Traits of antennae - Antennae and No antennae

<u>Given:</u>

<u />

Tall-antennae (46) and dwarf-no antennae (42) are the wild type.

Dwarf- antennae (7) and tall- no antennae (5) are the recombinants.

Total possibilities = 100

Recombinant frequency = \frac{7}{100} + \frac{5}{100}

Recombinant frequency = \frac{12}{100}

Recombinant frequency in percentage = \frac{12}{100} X 100 = 12%

Therefore, recombinant frequency between T and A is 12%

8 0
3 years ago
Plz Helppp meeee assapppp
Gwar [14]

Given:

A right angled triangle.

To find:

The value of x.

Solution:

We have,

Base = x

Hypotenuse = \sqrt{5}

In a right angle triangle,

\cos \theta = \dfrac{Base}{Hypotenuse}

For the given triangle,

\cos 45^\circ= \dfrac{x}{\sqrt{5}}

\dfrac{1}{\sqrt{2}}= \dfrac{x}{\sqrt{5}}

Multiply both sides by \sqrt{5}.

\dfrac{\sqrt{5}}{\sqrt{2}}= x

\dfrac{\sqrt{5}}{\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}= x

\dfrac{\sqrt{10}}{2}= x

Therefore, the required value of x is \dfrac{\sqrt{10}}{2}.

8 0
3 years ago
What is 35% of 107<br>0.35(10) =​
NISA [10]

Answer:

37.45percent

our output is 100

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similarity x equals 35 percent

3 0
4 years ago
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