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ikadub [295]
2 years ago
12

I need help but this is the question

Mathematics
1 answer:
MrRissso [65]2 years ago
5 0

Answer:

what is the question ?

Step-by-step explanation:

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Find the least 2-digit whole number N so that the sum 2^9+2^4+N is a perfect square.
oksano4ka [1.4K]

Answer:

N=48

Step-by-step explanation:

2^9+2^4+48=576

576 is a perfect square

3 0
2 years ago
Please help it's 20 and 22 Find he value of the Variables
KIM [24]
20 x=5 I hope this helps
22.x=15
3 0
3 years ago
Julie is a cashier. She can ring up 12 customers in 9 mintesutes. At the rate, how many minutes does it take for her to ring up
oksano4ka [1.4K]

Answer:

5.2

Step-by-step explanation:

ok so we need to find the unit rate( how many customers per minute) and thats 12 divided by 9 which is 1.3 minutes per customer so now we need to find what 1.3 minutes is x4 customers. This brings us to 5.2.

6 0
2 years ago
Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul
natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

\bf B=\displaystyle\frac{L}{4\pi d^2}

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of  Alpha Centauri A is

\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728

According to the inverse square law for light intensity

\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}

where

\bf I_1= light intensity at distance \bf d_1  

\bf I_2= light intensity at distance \bf d_2  

Let \bf d_2  be the distance we would have to place the 50-watt bulb, then replacing in the formula

\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0
3 years ago
What is the slope of the line that contains these points? xxx -4−4minus, 4 -3−3minus, 3 -2−2minus, 2 -1−1minus, 1 yyy 222 555 88
Charra [1.4K]

Given:

The table of values is

x        y

-4      2

-3      5

-2       8

-1       11

To find:

The slope of the line that contains these points.

Solution:

From the given table consider any two point.

Let the line passes through the points (-4,2) and (-3,5). So, the equation of the line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-2=\dfrac{5-2}{-3-(-4)}(x-(-4))

y-2=\dfrac{3}{-3+4}(x+4)

y-2=\dfrac{3}{1}(x+4)

Using distributive property, we get

y-2=3x+12

y=3x+12+2

y=3x+14

Therefore, the required equation of line is y=3x+14.

4 0
3 years ago
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