All categories

4 years ago

Solve 5x^3 - 3x^2 - 14x

Mathematics

1 answer:

Pie4 years ago

7 0

<h3>I’ll teach you how to solve 5x^3 - 3x^2 - 14x</h3>

--------------------------------------------------------

5x^3 - 3x^2 - 14x

Factor out the common term x:

x(5x^2 - 3x 14)

Factor 5x^2 - 3x 14:

Break the expression into groups:

(5x62+7x)+(-10x-14)

Factor out x from 5x^2+7x:

x(5x+7)

Factor out -2 from -10x-14:

-2(5x+7)

x(5x+7)-2(5x+7)

Factor out the common term 5x+7:

(5x+7)(x-2)

x(x+7)(x-2)

Your Answer Is x(x+7)(x-2)

Plz mark me as brainliest :)

You might be interested in

What is the average speed that robin mus drive to reach her friend's house 170 miles away in 2 1/2 hr

Tamiku [17]

68 miles / hour

Average speed = distance / time

distance = 170 and time = 5/2 ( as an improper fraction)

speed = 170 ÷ $\frac{5}{2}$ = 170 × $\frac{2}{5}$ = $\frac{340}{5}$ = 68

4 0

3 years ago

Read 2 more answers

What is the equation of the line through the origin and (-5, 6) <br><br>I hate try it's .-.

vazorg [7]

Answer:

$y=-\frac{6}{5} x$

Step-by-step explanation:

$y=-6/5x+0$

$y=-6/5x$

6 0

3 years ago

Read 2 more answers

1. Locate and label the following numbers on the number line:

n200080 [17]

Answer:

1/4 is your answer

Step-by-step explanation:

8 0

3 years ago

Heather practices soccer and piano. Each day she practices piano for 2 hours. After 5 days, she practiced both piano and soccer

irina [24]

She practiced for 4 hrs
4×5=20

5 0

3 years ago

Determine the greatest common divisor of the elements of the set \[ s = \{ n^{13} - n \mid n \in \mathbb{z} \}. \]

Kay [80]

Answer:

2730

Step-by-step explanation:

We want to determine the greatest common divisor of the elements of the set $S = \{ n^{13} - n \mid n \in \mathbb{Z} \}.$

We apply the Fermat's little theorem which states that if p is a prime number, then for any integer a, the number aᵖ − a is an integer multiple of p.

Now, $n^{13} \equiv n \mod p$ if p-1 divides 12.

Since the of 12 are 1,2,3,4, 6, 12, the corresponding primes are 2, 3, 5, 7, 13.

Therefore, the gcd of the elements in $2^{13}-2$ and $3^{13}-3$ is 2 \cdot 3 \cdot 5 \cdot 7 \cdot 13.$

2*3*5*7*13=2730

Therefore, the gcd of the elements in set S is 2730.

5 0

3 years ago