Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers
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I think i know this one. it's 3,281.
I'm assuming you are referring to the radius of a square
The first thing we have to do is divide by pi, because it's the last thing you do when calculating the area.
2289.06/3.14
729
Now, we have to take the square root of this number because the radius in the area formula is squared.
729^1/2
27
So, the radius is 27.
Step-by-step explanation:
I used a co-ordinate graph and place the ticket booth at the origin then I chose difference of four but you can choose any and place three events equidistant from the origin by using the X- and Y- axis to easily determined a distance of 4 from the origin .
(0-4, 0) =( 4,0)
(0+4, 0) = (4 ,0)
(0, 0+4) = (0, 4)
if the both are placed first u would need to find the equation of a circle that contains all three points and place the booth at centre
you do this by creating the system of 3 equations inputting the x,y coordinates of each booth and solving for h,k,r
equation of a circle (X-H) 2 +( Y-K) 2 = r2
Hope It helps
:DD have a nice day
