( c^2 )^3 = 64 <=>( c^2 )^3 = 4^3 <=> c^2 = 4 <=> c = 2 or c = -2.
You are going in the right direction. For the distance of ST I get √136
√(-5-1)² + (6+4)² =
√(-6)² + (10²) =
√ 36 + 100 =
√136
√34² + √136² =√170²
34 + 136 = 170
170 = 170
Answer:
The answer is a isosceles right I think.
The volume a cylinder is v=(area of base)h and since the area of the base is πr², you can write the equation a v=πr²h. Since the problem wants us to find what be is in the equation of a cylinder as v=Bh, we know that B=πr². The problem gave us the diameter of the circle so we no the radius is going to be the diameter (24) divided by 2 which equals 12. therefore B=12²π.
I hope this helps.
Area = r^2 x PI
to find r take the square root of the area:
r = √100 = 10
The circumference of a circle is the diameter times PI.
The diameter is 2 times r = 2 x 10 = 20
The circumference = 20PI m
The answer is C.
