The code for a lock consists of 3 digits using the digits: 1,2,4,7,8,9. How many different codes are possible if no digit may be
1 answer:
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Answer:
Step-by-step explanation:
a) To find the length of diagonal XT, we can use the distance formula to get
Since this is a rectangle, XT=YW, meaning YW=10 as well.
b) The area of a rectangle is given by length times width. The length is |-3-5|=8, and the width is |-2-4|=6. So the area is (8)(6)=48.
c) The perimeter is just 2(8+6)=28.
<h3>Answer: B. (-1, 0)</h3>
This point is below both the red diagonal line and the blue parabola. We know that the set of solution points is below both due to the "less than" parts of each inequality sign.
In contrast, a point like (2,2) is above the parabola which is why it is not a solution. It does not make the inequality true. So this is why we can rule choice A out.
Choice C is not a solution because (4,1) does not make true. This point is not below the red diagonal line. We can cross choice C off the list.
Choice D is similar to choice A, which is why we can rule it out as well.