An alternating series
converges if
is monotonic and
as
. Here
.
Let
. Then
, which is positive for all
, so
is monotonically increasing for
. This would mean
must be a monotonically decreasing sequence over the same interval, and so must
.
Because
is monotonically increasing, but will still always be positive, it follows that
as
.
So,
converges.
Answer:
Do not reject 
Step-by-step explanation:
From the question we are told that
Sample size 
Sample size 
Sample proportion 1 
Sample proportion 2 
95% confidence interval
Generally for 95% confidence level
Level of significance
Therefore
Generally the equation for confidence interval between 
is mathematically given as
Therefore
Confidence interval is
Conclusion
Given the confidence interval has zero
Therefore do not reject
Simplify each side in order to determine if true.
the answer is: False
Answer:
A 5
Step-by-step explanation:
Parts on the left have the same ratio as parts on the right.
... x/(x+5) = (x -2)/(x +1)
Multiplying by (x+5)(x+1), we get
... x(x +1) = (x -2)(x +5)
... x² +x = x² +3x -10 . . . . eliminate parentheses
... 0 = 2x -10 . . . . . . . . . . subtract x²+x
... 0 = x -5 . . . . . . . . . . . . divide by 2
... 5 = x . . . . . . . . . . . . . . . add 5
