We can let
a = 1/(x-1)
b = 1/(y+2)
and rewrite the equations as
2a - b = 10
a + 3b = -9
Using the first to write an expression for b, we get
b = 2a - 10
Substituting this into the second equation gives
a + 3(2a -10) = -9
7a -30 = -9 . . . . . . . . simplify
7a = 21 . . . . . . . . . . .add 30
a = 3
b = 2·3 - 10 = -4
Now, we can find x and y.
3 = 1/(x -1)
x - 1 = 1/3
x = 1 1/3 = 4/3
-4 = 1/(y +2)
y +2 = -1/4
y = -2 1/4 = -9/4
Then the desired sum is
x + y = 4/3 -9/4 = (16 -27)/12
x + y = -11/12
The appropriate choice is ..
c. -11/12
The square root of a prime number (11) is irrational
7x/x-4 * x/x+7
mutiply the numerators together
(7x)(x)= 7x^ 2
mutiply the denominators together
(x-4)(x+7)
(x)(x)(7)(x)= x^2+7x
(-4)(x)(-4)(7)= -4x-28
x^2+7x-4x-28
x^2+3x-28
Answer:
7x^2/x^ 2+3x-28
The determinant of a 2 x 2 matrix can be calculated as:
Product of non-diagonal elements subtracted from product of diagonal elements.
The diagonal elements in given matrix are 12 and 2. The non-diagonal elements are -6 and 0.
So,
Determinant G = 12(2) - (-6)(0)
Determinant G = 24 - 0 = 24
So, option B gives the correct answer
Answer:
greater
Step-by-step explanation:
