Answer:
Parabola with vertex at point (1,0) that goes to the right (see attached diagram).
Step-by-step explanation:
Let the complex number z be
then
and
Thus,
Square it:
This is the equation of parabola with vertex at point (1,0) that goes to the right.
5x+15-6+7x
15-6= 9.
5=7= 12
12x+9 .
![\bf \textit{zeros at } \begin{cases} x = -3\implies &x+3=0\\ x = -1\implies &x+1=0\\ x = 4\implies &x-4=0 \end{cases}\qquad \implies (x+3)(x+1)(x-4)=\stackrel{y}{0} \\\\\\ (x^2+4x+3)(x-4)=0\implies x^3~~\begin{matrix}+ 4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+3x~~\begin{matrix} -4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-16x-12=0 \\\\\\ x^3-13x-12=0](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bzeros%20at%20%7D%20%5Cbegin%7Bcases%7D%20x%20%3D%20-3%5Cimplies%20%26x%2B3%3D0%5C%5C%20x%20%3D%20-1%5Cimplies%20%26x%2B1%3D0%5C%5C%20x%20%3D%204%5Cimplies%20%26x-4%3D0%20%5Cend%7Bcases%7D%5Cqquad%20%5Cimplies%20%28x%2B3%29%28x%2B1%29%28x-4%29%3D%5Cstackrel%7By%7D%7B0%7D%20%5C%5C%5C%5C%5C%5C%20%28x%5E2%2B4x%2B3%29%28x-4%29%3D0%5Cimplies%20x%5E3~~%5Cbegin%7Bmatrix%7D%2B%204x%5E2%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%2B3x~~%5Cbegin%7Bmatrix%7D%20-4x%5E2%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~-16x-12%3D0%20%5C%5C%5C%5C%5C%5C%20x%5E3-13x-12%3D0)
we know that f(-2) = 24, namely when x = -2, y = 24, let's see if that's true
darn!! no dice.... hmmmm wait a second.... 4 * 6 = 24, if we could just use a common factor of 4 on the function, that common factor times 6 will give us 24, let's check.
![\bf 4(x^3-13x-12)=y\implies \stackrel{x = -2}{4[~~(-2)^3-13(-2)-12~~]}=y \\\\\\ 4[~~-8+26-22~~]=y\implies 4[6]=y\implies 24=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 4x^3-52x-48=y~\hfill](https://tex.z-dn.net/?f=%5Cbf%204%28x%5E3-13x-12%29%3Dy%5Cimplies%20%5Cstackrel%7Bx%20%3D%20-2%7D%7B4%5B~~%28-2%29%5E3-13%28-2%29-12~~%5D%7D%3Dy%20%5C%5C%5C%5C%5C%5C%204%5B~~-8%2B26-22~~%5D%3Dy%5Cimplies%204%5B6%5D%3Dy%5Cimplies%2024%3Dy%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%204x%5E3-52x-48%3Dy~%5Chfill)
1) 0.07 zeros only matter if there is a non-zero digit, as well as the decimal to the left of it
2)90,000 it would have been 89000 if the 972 had been an 872
3).00420 must include the last zero, it is considered significant because of the reason in number one
