Answer:
a) T test
b) Claim
because critical value is not equal to test statistic then reject null hypothesis
Step-by-step explanation:
Construction of hypothesis
H₀ : p = 75
H₁ : p ≠ 75
Here Standard deviation = 7
sample = n = 50
Average = x-bar = 78
Level of significance:
∝ = 5% = 0.05
Degree of freedom:
df = n-1
= 50 -1 = 49
Critical value :
± 1.96
a) T test
test t is used as average X mean is used
Test Statistic:
t = X₂ - X₁ / Sd /√n
= 78 - 75 / 7/√50
=3.0304
Critical region :
We take two tail T test
test statistic is in reject interval. Reject H₀
b) Claim
because critical value is not equal to test statistic then reject null hypothesis
It is rational because the square root of 25 is 5.
X+8=18 -8 -8
X=10 Value of x is 10
The volume of a cone is 84.78 cm
<u>Step-by-step explanation</u>:
<u>Given</u>:
radius = 3 cm and
height = 9 cm
<u>To Find</u>:
The Volume of a Cone
<u>Formula</u>:
The Formula for the volume of a cone is
V=πr2 *h/3
<u>Solution</u>:
V=πr2 *h/3
π value is 3.14
V= 3.14*(3)^2*9/3
V=3.14*9*3
V= 84.78 cm
Therefore the volume is 84.78 cm.
We know that
the scale (cm/feet)-----------> 1/2
1 in-------------> 2.54 cm
x in---------------> 1 cm
X=1/2.54------> 0.3937 in
so
the new scale (in/feet)------------> 0.3937 in/ 2 feet-------> 0.1969 in/feet
the answer is
0.1969 in/feet
