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3 years ago

Does anyone understand I really dont get this

Mathematics

1 answer:

Nat2105 [25]3 years ago

3 0

I'm sorry hun, i suck at math. If i knew how i would help you. Have you tried looking it up?

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Plsssss help I’ll put you as a brainiest answer

Svet_ta [14]

Answer:

your answer would probably be 20 bc I times 5 then times 2 then I got 10. Then I did 10 X 2 and I got 20

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3 years ago

An invoice quotes a price of $620 subject to discounts of 30%, 15%, and 5%. What is the selling price? (Round off your answer to

Eddi Din [679]

Selling price=620(1-0.30)(1-0.15)(1-0.05)
selling price = 620(.7)(.85)(.95) = 350.46

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3 years ago

A timer is started and a few moments later a swimmer dives into the water and then comes back up. The swimmer’s depth (in feet)

zhannawk [14.2K]

Answer: The swimmer dives into the water 5 seconds after the timer is started.

The swimmer comes back up 11 seconds after the timer is started.

Step-by-step explanation:

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2 years ago

Find the equation of the line perpendicular to y=3/2x-9 and passes through the point (6,2)

lys-0071 [83]

Answer:

y=-2/3x-2

Step-by-step explanation:

slope= -2/3

y=-2/3x+b

enter the given points

2=4+b

b=-2

y=-2/3x-2

6 0

3 years ago

The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width

blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given perimeter

perimeter of rectangle = 2 ( length + width )

=> 30.8 km = 2 ( x + y )

=> $x + y = \frac{30.8}{2}$

=> y = 15.4 – x ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,

=> $length^2 + width^2 = diagonal^2$

=> $x^2 + y^2 = 11^2$

=> $x^2 + y^2 = 121$

On substituting value of y from (1) in above equation we get

=> $x^2 + (15.4-x)^2 = 121$

=> $x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x = 121$

=> $2x^2-30.8x + 237.16 -121 = 0$

=> $2x^2-30.8x + 116.16 = 0$

Solving above quadratic equation using quadratic formula

General form of quadratic equation is

$ax^2 +bx +c = 0$

And quadratic formula for getting roots of quadratic equation is

$x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}$

As equation is $2x^2-30.8x + 116.16 = 0$ , in our case

a = 2 , b = -30.8 and c = 116.16

Calculating roots of the equation we get

$x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}$

$x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{(30.8\pm29.33)}4$

$x=\frac{(30.8+29.33)}{4}$

$x=\frac{(30.8-29.33)}{4}$

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0

3 years ago