The distance of the ball from the foot of the tower is : 35.18m
The ball would be moved 57.2m away from the foot of the tower for the Angle of elevation to be halved.
<h3>What is angle of elevation?</h3>
Angle of elevation is the angle formed between the horizontal and the line of view from the vertical.
Analysis:
The height of the tower and the distance of the ball from the foot of the tower form a right angle triangle.
so we use trigonometry.
a) let distance of the ball from foot of tower be x.
so that, tan 52 = 45/x
x = 45/tan52
x = 45/1.279 = 35.18m
b) let the distance of the ball in the new position from the foot of the tower be y.
if the angle of elevation is halved, then new angle is 52/2 = 26°
tan 26 = 45/y
y = 45/tan26 = 45/0.487 = 92.4m
distance moved from old position to new position = 92.4 - 35.18 = 57.2m
In conclusion, the distance of the ball from the foot of the tower and the distance the ball should move to make its elevation 26° are 35.18m and 57.2m respectively.
Learn more about angle of elevation: brainly.com/question/88158
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<span>Think of arcsin (-1/3) as an angle, and call it "theta." The the original problem becomes "find sec [ 2 theta ]"
1 1
which is the same as "find ------------------ " or --------------------------------------
cos[2 theta] (cos theta)^2 - (sin theta)^2
Recall that theta = the angle whose sine is -1/3. Thus, sin theta = -1/3 and cos theta = 2sqrt(2) / 3.
So we now have:
1
-------------------------------------------
2 sqrt(2) -1
[------------------- ]^ 2 - [ ------- ]^2
3 3
which boils down to:
1 1
----------------- = ---------------- = 9/7 (answer)
8 1 7/9
------ - --------
9 9
</span>
The answer is actually cube A
Answer:
The answer would be "at 6 degree change throughout the day"
Answer:
.
Step-by-step explanation:
