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Tema [17]
4 years ago
5

Could someone explain.This brainliest.

Mathematics
1 answer:
LekaFEV [45]4 years ago
4 0

Mikayla-132\\\\Zack:\\one\ fourth\ as\ much\ candy\ as\ Mikayla\\\\\dfrac{1}{4}\cdot132=\dfrac{132}{4}=33\\\\Kim:\\three\ times\ as\ much\ candy\ as\ Zack\\\\3\cdot33=99\\\\Answer:\ 132+33+99=264\ pieces

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What set or sets of real numbers does -√16 belong to?
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Answer:

Step-by-step explanation:

Well the square root of 16 can be simplified to 4, which can be represented as a fraction: 4/1, so it's not irrational, but rather rational.

Whole numbers are similar to integers, and natural numbers, the only difference is integers includes all real numbers, which do not have a decimal value. So this includes negative numbers, zero, and positive numbers.

Whole numbers include all real numbers, which do not have a decimal value, and are greater than or equal to zero, or in other words, not negative.

Natural numbers include all real numbers, which do not have a decimal value, and are greater than zero, or in other words, positive numbers.

So this number is a integer, and rational number. (since the negative number in front of the radical)

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2 years ago
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How do you graph this f(x)= -3/2|x|+5 if x≤4​
LenaWriter [7]

Answer:

  see below

Step-by-step explanation:

I enter the equation into a graphing calculator and let it do the graphing.

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If you're graphing this by hand, you start by looking for the parent function. Here, it is |x|. That has a vertex of (0, 0) and a slope of +1 to the right of the vertex and a slope of -1 to the left of the vertex.

Here, the function is multiplied by -3/2, so will open downward and have slopes of magnitude 3/2 (not 1). The graph has been translated 5 units upward, so the vertex is (0, 5).

I'd start by plotting the vertex point at (0, 5), then identifying points with slope ±3/2 either side of it. To the left, it is left 2 and down 3 to (-2, 2). The points on the right of the vertex are symmetrically located about the y-axis, so one of them will be (2, 2).

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Answer:

C. the graph of g(x) is shifted 3 units up.

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The statement that compares the graph of g(x) with the graph of f(x) is that the graph of g(x) is shifted 3 units up.

If we have the equation:

G(x) = F(x) + 3

Then, the graph of G(x) will be composed of points 3 units above the graph of F(x).

Conversely, the difference between F(x) and G(x) at any particular value of x will always be 3.

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