Answer:
(s-t)(-1) = -1
(s+t)(-1) = -7
Step-by-step explanation:
Given the following set of functions
s(x)=2x-2
t(x)=3x
(s-t)(x) = s(t) - t(x)
(s-t)(x) = 2x - 2 - 3x
(s-t)(x) = -x -2
(s-t)(-1) = -(-1) - 2
(s-t)(-1) = 1-2
(s-t)(-1) = -1
(s+t)(x) = s(t) + t(x)
(s+t)(x) = 2x - 2 + 3x
(s+t)(x) = 5x -2
(s+t)(-1) = 5(-1) - 2
(s+t)(-1) = -5-2
(s+t)(-1) = -7
Answer:
the 2nd one
Step-by-step explanation:
Step-by-step explanation:
a^2 + b^2 = c^2
(x+2)^2 + 4x^2 = (3x+4)^2
(x+2)(x+2)+ 4x^2= (3x+4)(3x+4)
x^2 + 2x + 2x + 4 + 4x^2 = 9x^2 + 12x + 12 x + 16
5x^2 + 4x + 4 = 9x^2 + 24x + 16
-4x^2 - 20x - 12 = 0
now we can use the quadratic formula
(-b±√(b²-4ac))/(2a)
I can't type all this so
.....
x = -0.697224362 or -4.302775638
AB can't be negative so it's the first one
so it's equals to 1.302775638
To resolve the proposed issue, an explanation is needed in which the subject is addressed
