Answer:

Step-by-step explanation:
For Q1 and Q2


For Q3 and Q4

The answer is 2.25h when we do theese equation
95-50=45
45/20=2.25h
<span>x = 9
Since ZP bisects â OZQ, that means that the measurements for â OZP and â PZQ are the same. So create an equation with their respective values set to each other.
8x - 9 = 5x + 18
Now solve for x
8x - 9 = 5x + 18
Subtract 5x from both sides
3x - 9 = 18
Add 9 to both sides
3x = 27
Divide both sides by 3
x = 9</span>