Assuming the weights are in kilograms, what is the mystery weight of y? use the equation you created in part a to find the solut
1 answer:
The equation which we have created showing relationship between weights of both sides has a solution of y=1/2.
Given weight on one end is y+y+y+1+1+1 and weight on other end is y +y+ y+ y+2 where y is mystery weight.
We have to first form an equation.
If we see the figure we can notice that both sides are equal to other, it means the weight of both ends are equal to each other.
Equation is relationship between two or more variables expressed in equal to form. It is solved to find the value of variables. Equation of two variables look like ax+ by=c.
y+y+1+1+1=y+y+y+y+2
2y+3=4y+2
2y-4y=2-3
-2y=-1
y=1/2
Hence the solution of the equation a showing relationship between weights on both ends is y=1/2.
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Question is incomplete as it should include the given figure.
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Answer:
Step-by-step explanation:
Given that a dairy scientist is testing a new feed additive. She chooses 13 cows at random from a large population of cows. She randomly assigns nold = 8 to get the old diet, and nnew = 5 to get the new diet including the additive.
From the data given we get the following
N Mean StDev SE Mean
Sample 1 8 43 5.1824 1.832
Sample 2 5 73 21.0832 9.429
df = 11
Std dev for difference = 13.3689
a) Yes the two are independent. The two sets of cows randomly chosen are definitely independent. Paired means equal number should be there and homogeneous conditions should be maintained.
b) Enclosed
c) Comparison of two means is the test recommended here. Because independent samples are used.\
d) Test statistic= -3.1233
(because of unequal variances we use that method)
95% confidence interval = ( -56.6676 , -3.3324 )
p value <0.05 our alpha
So reject null hypothesis.
The two means are statistically significantly different.
