F(x) = x^3 - 2x^2 - 6x + 12 = 0
lets try substituting some of the factors of 12:-
f(2) = 8 - 8 -12+12 = 0 So one zero is x = 2 Answer
Dividing f(x) by (x - 2) we get:-
x^2 - 6 so the other 2 zeros are sqrt6 and - sqrt6 or 2.45 and -2.45 to the nearest hundredth Answer
Answer:
136
Step-by-step explanation:
Let x be the width of the sidewalk and the area becomes:
A=LW and L=6+2x and W=4+2x now we have
A=(6+2x)(4+2x) and we are told that A=48ft^2
48=24+20x+4x^2
4x^2+20x-24=0
4(x^2+5x-6)=0
x^2+5x-6=0
x^2-x+6x-6=0
x(x-1)+6(x-1)=0
(x+6)(x-1)=0
So x=-6, 1, however since x is a measurement it must be positive thus
x=width=1 ft is the only possible solution.
.048t = 188,900 (This side will have the total increase after being divided by % and X amount of years)
Answer:
x = 49
Step-by-step explanation:
The angles are complementary so they add to 90 degrees
41+x = 90
Subtract 41 from each side
41+x-41 = 90-41
x = 49
