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Nitella [24]
3 years ago
15

Sean’s house is currently worth $188,900 according to the realtor house prices and Shawn‘s neighborhood will increase by 4.8% ev

ery year the given function represents the value of Shauns house after t years
Mathematics
2 answers:
Sloan [31]3 years ago
6 0

Answer:

The expression (1.0118)^{4t} reveals the approximate quarterly growth rate of the value of Sean's house.

MaRussiya [10]3 years ago
3 0
.048t = 188,900 (This side will have the total increase after being divided by % and X amount of years)
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A hotel installs smoke detectors with adjustable sensitivity in all public guest rooms. (a) State the null and alternative hypot
Lana71 [14]

Answer:

(a) <em>H₀</em>: There is no fire vs. <em>Hₐ</em>: There is a fire.

(b) A type I error occurs when we discard a true null hypothesis (<em>H₀</em>) and a type II error is made when we fail to discard a false null hypothesis (<em>H₀</em>).

(c) In this case, type II error has the more severe consequences.

Step-by-step explanation:

It is provided that a hotel installs smoke detectors with adjustable sensitivity in all public guest rooms.

(a)

The hypothesis can be defined as follows:

<em>H₀</em>: There is no fire.

<em>Hₐ</em>: There is a fire.

(b)

A type I error occurs when we discard a true null hypothesis (<em>H₀</em>) and a type II error is made when we fail to discard a false null hypothesis (<em>H₀</em>).

In this case a type I error will be committed if we conclude that there is a fire and the smoke detector sounds an alarm, when in fact there is no fire.

In this case a type II error will be committed if we conclude that there is no fire and the smoke detector does not sounds an alarm, when in fact there is a fire.

(c)

In this case, type II error has the more severe consequences.

Concluding that there is no fire as the smoke detector did not sound an alarm, when in fact there is a fire, will cause casualties and is harmful for the health of the guests.

Guests would not be alert about the fire as there was not any alarm, and many may loose their lives because of this.

7 0
3 years ago
Please answer correctly, will mark brainliest
wel

Answer:

Since the values vary from 0.5 to 4.5, let's take 5 intervals of width 1 unit each

(Lower boundary is included, upper boundary is not)

Average

no. of --------> frequency

movies

_______ __________

0 - 1 --------------> 1

1 - 2 --------------> 5

2 - 3 --------------> 5

3 - 4 --------------> 2

4 - 5 --------------> 1

For frequencies, just count the data values in each interval

6 0
3 years ago
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