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Dmitry [639]
2 years ago
8

Which angle is in standard position?

Mathematics
2 answers:
FrozenT [24]2 years ago
8 0

Answer:

its the first graph

Step-by-step explanation:

i hope this is what you were looking for ;)

Anni [7]2 years ago
4 0

Answer:

An angle is in standard position, if its vertex is located at the origin and one ray is on the positive x-axis.

Step-by-step explanation:

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Vertical angles are equal. What is the degree <2 and <3?
enyata [817]

Answer:

Angle 2 is 145

Angle 3 (and 1) is: 35

Step-by-step explanation:

Angles together will create 360 degrees. 145*2 = 290. 360 -290 = 70

70/2 = 35

8 0
3 years ago
Read 2 more answers
The value of Jim's telephone calling card decreases 15 cents for every minute he uses it. Yesterday he used the card to make a 6
Alja [10]

Answer:

90 cent

Step-by-step explanation:

15*6=90

4 0
2 years ago
cuanto dinero se debe invertir a un interes de 14% compuesto continuamente para tener $500,000 en 35 años?
Alja [10]

Answer:

Se necesita depositar un capital inicial de $ 5096.83 pesos para lograr $ 500000 pesos a un interés compuesto de 14 % anual luego de 35 años.

Step-by-step explanation:

La cantidad ahorrada bajo interés compuesto está definida por la siguiente fórmula:

C(t) = C_{o}\cdot (1+r)^{t} (1)

Donde:

C_{o} - Capital inicial, medido en pesos.

C(t) - Capital actual, medido en pesos.

r - Tasa de interés, sin unidad.

t - Anualidad, medida en años.

Asumiendo que la tasa de interés compuesto es anual y si C(t) = 500000, r = 0.14 y t = 35, entonces el capital inicial es:

C_{o} = \frac{C(t)}{(1+r)^{t}}

C_{o} = \frac{500000}{(1+0.14)^{35}}

C_{o} = 5096.83

Se necesita depositar un capital inicial de $ 5096.83 pesos para lograr $ 500000 pesos a un interés compuesto de 14 % anual luego de 35 años.

6 0
2 years ago
8.Find the value of c that makes the expression be a perfect square trinomial p^2-30p+c
Darina [25.2K]
Hope this is the right one.

Problem 8
p^2 - 30p + c
<em>Step One</em>
Take 1/2 of - 30
1/2 * -30 = - 15

<em>Step 2
</em>Square -15
(-15)^2 = 225
c = 225

Problem Nine
\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a} &#10;
a = 1
b = 4
c = -15
\text{x = }\dfrac{ -4 \pm \sqrt{4^{2} - 4*1*(-15) } }{2*1}
\text{x = }\dfrac{ -4 \pm \sqrt{\text{16} + \text{60} } }{2}

x = [-4 +/- sqrt(76)] / 2
x = [-4 +/- 2*sqrt19]/2
x = [-4/2 +/- 2/2 sqrt[19]
x = - 2 +/- sqrt(19) 

x1 = - 2 + sqrt(19)
x2 = -2 - sqrt(19)

These two can be broken down more by finding the square root. I will leave them the way they are.  It's just a calculator question if you want it to go into decimal form.

Problem Ten

a = 1
b = 4
c = -32

The discriminate is sqrt(b^2 - 4ac)
D = sqrt(b^2 - 4ac)
D = sqrt(4^2 - 4(1)(-32)
D = sqrt(16 - - 128)
D = sqrt(16 + 128)
D = sqrt(144)
D = +/- 12

Since D can equal + or minus 12 there must be 2 possible (and different) roots. As a matter of fact, this quadratic can be factored.
(x + 8)(x - 4) = y 
But that' s not what you were asked for.
The discriminate is >  0 so the roots are going to be real.
<em>Answer; The discriminate is > 0 so there will be 2 real different roots.</em>

4 0
2 years ago
HEPL MEE, I NEED EXTREME HELP!
natta225 [31]

Answer:

A= ( 5 x 3 ) x [(9-5)x3 divided by 2]

15+6

=21

P= 5+5+3+9

=22

6 0
2 years ago
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