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sweet [91]
3 years ago
6

How often do most entrepreneurs

Business
1 answer:
madam [21]3 years ago
7 0

Answer:

B. they spend every other day making decisions, because with every passing day trends changes.

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Identifying a single overhead rate as the predetermined overhead rate (b)
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El costo de producir x artículos está dado por yc= 3.5x + 852. Cada artículo se vende a $5, por lo que el ingreso por vender "x"
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I don't talk Spanish why ;-;
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On May 25, after the transactions had been posted, Adams discovered that the following entry contains an error. The cash receive
vampirchik [111]

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With the correcting entry method, the wrongly posted account will transfer the amount that was to be posted elsewhere to the place it was to be posted in. In this case the posting was to be to Accounts Receivable not Service fees so:

Date                   Account Title                                     Debit                  Credit

May 23              Service Fees                                   $1,270

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3 0
3 years ago
A company is considering buying a new piece of machinery. A 10% interest rate will be used in the computations. Two models of th
JulsSmile [24]

Answer:

Machine I

capitalized cost:  230,271.28

EAC: $ 27,047.58

Machine II

EAC:  $ 27,377.930  

As Machine I cost per year is lower it is better to purchase that one.

Annual deposits to purchase Machine I in 20 years: $ 1,396.770  

return of machine I with savings of 28,000 per year: 10.51%

Explanation:

WE calculate the present worth of each machine and then calculate the equivalent annual cost:

MACHINE 1

Operating cost:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\  

C 18,000

time 20

rate 0.1

18000 \times \frac{1-(1+0.1)^{-20} }{0.1} = PV\\  

PV $153,244.1470  

Salvage value:

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $20,000.0000  

time   20.00  

rate  0.1

\frac{20000}{(1 + 0.1)^{20} } = PV  

PV   2,972.87  

Total: -80,000 cost - 153,244.15 annual cost + 2,972.87 salvage value:

Total: 230,271.28

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\  

Present worth  $(230,271.28)

time 20

rate 0.1

-230271.28 \div \frac{1-(1+0.1)^{-20} }{0.1} = C\\  

C -$ 27,047.578  

Fund to purchase in 20 years:

FV \div \frac{(1+r)^{time} -1}{rate} = C\\  

FV  $80,000.00  

time 20

rate 0.1

80000 \div \frac{(1+0.1)^{20} -1}{0.1} = C\\  

C  $ 1,396.770  

IF produce a 28,000 savings:

we must solve using a financial calcualtor for the rate at which the capitalized cost equals 28,000

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\  

PV  $230,271.28  

time 20

rate 0.105126197

230271.28 \div \frac{1-(1+0.105126197287798)^{-20} }{0.105126197287798} = C\\  

C  $ 28,000.000  

rate of 0.105126197 = 10.51%

<u>Machine II</u>

100,000 cost

25,000 useful life

15,000 operating cost during 10 years

20,000 for the next 15 years

Present value of the operating cost:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\  

C 15,000

time 10

rate 0.1

15000 \times \frac{1-(1+0.1)^{-10} }{0.1} = PV\\  

PV $92,168.5066  

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\  

C 20,000

time 15

rate 0.1

20000 \times \frac{1-(1+0.1)^{-15} }{0.1} = PV\\  

PV $152,121.5901  

in the timeline this is at the end of the 10th year we must discount as lump sum for the other ten years:

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $152,121.5901  

time   10.00  

rate  0.1

\frac{152121.590126167}{(1 + 0.1)^{10} } = PV  

PV   58,649.46  

salvage value

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $25,000.0000  

time   25.00  

rate  0.1

\frac{25000}{(1 + 0.1)^{25} } = PV  

PV   2,307.40  

Total cost: 100,000 + 92,168.51 + 58,649.46 - 2,307.40 = $248,510.57

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\  

PV  $248,510.57  

time 25

rate 0.1

248510.57 \div \frac{1-(1+0.1)^{-25} }{0.1} = C\\  

C  $ 27,377.930  

4 0
4 years ago
Which of these is a beneficial effect of monerans?
Marina86 [1]
You'll have to give me the options.
8 0
3 years ago
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