Since Sylvanite only contains 28% gold by mass, then to obtain 81.0 grams of gold, x amounts of sylvanite must be mined. To determine x, we divide 81 grams by 28%. This equation is shown below:
0.28X = 81
X = 81/0.28
X = 289.29 grams
Therefore, 289.29 grams of sylvanite must be dug up to obtain 81 grams of gold.
For this case, the first thing we must take into account is the following definition:
d = v * t
Where,
d: distance
v: speed
t: time
Substituting values we have:
Trip 1:
50 = v * t1
We cleared t1:
t2 = (50) * (1 / v)
Trip 2:
300 = (3 * v) * t2
We cleared t2:
t2 = (300/3) * (1 / v)
t2 = (100) * (1 / v)
Rewriting:
t2 = 2 (50) * (1 / v)
t2 = 2 * t1
Answer:
His new time compared with the old time was:
Twice the old time.
t2 = 2 * t1.
X=8 would you like me to explain why?
Answer:
C.
Step-by-step explanation:
5/8 = 20/32
20/32 ÷ 2 = 10/16
10/16 ÷ 2 = 5/8
