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Lunna [17]
3 years ago
7

HELP ASAP I need this done in less than 10 minutes

Mathematics
1 answer:
CaHeK987 [17]3 years ago
4 0

Answer:

why is it just black?

Step-by-step explanation:

???????

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Multiples of 9 less than 80
german
Multiples of nine: 9<span>,18,27,36,45,54,63,and 72</span>
6 0
3 years ago
The wildflowers at a national park have been decreasing in numbers. There were 300 wildflowers in the first year that the park s
Scorpion4ik [409]
Although the number of new wildflowers is decreasing, the total number of flowers is increasing every year (assuming flowers aren't dying or otherwise being removed). Every year, 25% of the number of new flowers from the previous year are added.
The sigma notation would be:
∑ (from n=1 to ∞) 4800 * (1/4)ⁿ , where n is the year. 
Remember that this notation should give us the sum of all new flowers from year 1 to infinite, and the values of new flowers for each year should match those given in the table for years 1, 2, and 3
This means the total number of flowers equals:
Year 1: 4800 * 1/4 = 1200 ]
+
Year 2: 4800 * (1/4)² = 300
+ 
Year 3: 4800 * (1/4)³ = 75
+  
Year 4: 4800 * (1/4)⁴ = 18.75 = ~19 (we can't have a part of a flower)
+
Year 5: 4800 * (1/4)⁵ = 4.68 = ~ 5
+ 
Year 6: 4800 * (1/4)⁶ = 1.17 = ~1
And so on. As you can see, it in the years that follow the number of flowers added approaches zero. Thus, we can approximate the infinite sum of new flowers using just Years 1-6:
1200 + 300 + 75 + 19 + 5 + 1 = 1,600

8 0
3 years ago
Our answer should be a complex number in the form a +bi where a and b are real numbers.
Otrada [13]

Answer:

16 +88i

Step-by-step explanation:

8 x (11i + 2 ) =

Distribute

8*11i + 8*2

88i +16

Writing in the proper form

16 +88i

6 0
3 years ago
+(7p-8q+6pq)+(q-2p+pq)-(10pq-p-4q)​
lilavasa [31]

Answer:

Step-by-step explanation:

3 0
3 years ago
Is the answer 3, 4, 5, or 6? need answer asap please! :)
-BARSIC- [3]
Don't touch the center. It is already even. 
Start anywhere by connecting a dotted line from one vertex to the next. To keep things so we know what we are talking about, go clockwise. Now you have 2 points that are Eulerized that were not before.

Skip and edge and do the same thing to the next two vertices. Those two become eulerized. Skip an edge and do the last 2.

Let's try to describe this better. Start at any vertex and number them 1 to 6 clockwise.
Join 1 to 2 
Join 3 to 4
Join 5 to 6

I think 3 is the minimum.
3 <<<< answer
4 0
3 years ago
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