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larisa86 [58]
3 years ago
5

The slope of the line is____

Mathematics
2 answers:
kotegsom [21]3 years ago
6 0

Answer:

nope

Step-by-step explanation:

Alisiya [41]3 years ago
5 0

Answer:

5/3

Step-by-step explanation:

rise/run

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Round 5,896,487 to the<br> nearest ten-thousand.
Bas_tet [7]

Answer:12

Step-by-step explanation:

u half to round it to the nerest hundreths and than multiplye it by 4

7 0
3 years ago
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Slope-intercept form of Slope = -9/5, y-intercept = -4
Brilliant_brown [7]

Answer:

y = - \frac{9}{5} x - 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{9}{5} and c = - 4 , thus

y = - \frac{9}{5} x - 4 ← equation of line

7 0
2 years ago
1. Convert 0.3 to a fraction and decimal.
Lubov Fominskaja [6]

Answer:

1=30%

2=0.09

3=37.5%

these is the answer

3 0
3 years ago
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Please answer ASAP I will give you five stars
Nataliya [291]

Known :

r = 6

h = 8

Asked :

V = ...?

Answer :

V = ⅓πr²h

= ⅓ × 3.14 × 6² × 8

= ⅓ × 3.14 × 36 × 8

= 3.14 × 12 × 8

= 301.44 units²

= <u>3</u><u>0</u><u>0</u><u> </u><u>units²</u> (rounded)

So, the volume of the cone is 300 units²

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

3 0
3 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
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