All categories

3 years ago

I will mark brainliest!!! Other answers: C. y=25x D. y=25x+8.34

Mathematics

2 answers:

saul85 [17]3 years ago

7 0

Answer:

y = 8.34x + 25

Step-by-step explanation:

(10, 108.4) (20, 191.8)

m = slope

m = (y2 - y1)/(x2 - x1)

m = 191.8 - 108.4/20 - 10

m = 83.4/10

m = 8.34

She collects rainwater in a large barrel that weighs 25 pounds (y-intercept) so therefore, our answer should be y = 8.34x + 25

goldfiish [28.3K]3 years ago

3 0

Answer:

Omg why are you soo beautiful? I love it

You might be interested in

Angles 8th grade math

fiasKO [112]

Yeah... I'm normal good at angles, but the way you've taken the picture, it's pretty hard for us to figure out. All you need to do is grab you protractor and start measuring. Pretty simple.<span />

7 0

3 years ago

Read 2 more answers

If the area of AABC is D, give the expressions that complete the equation for the measure of ZB?

Ira Lisetskai [31]

Given:

The figure of triangle ABC.

The area of the triangle ABC is D.

$m\angle B=\sin ^{-1}(\dfrac{m}{n})$

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

$Area=\dfrac{1}{2}\times base\times h$

Where, b is the base and h is the height of the triangle.

$Area=\dfrac{1}{2}\times a\times h$

The area of the triangle ABC is D.

$D=\dfrac{1}{2}\times a\times h$

$2D=ah$

$\dfrac{2D}{a}=h$ ...(i)

In a right angle triangle,

$\sin \theta =\dfrac{Perpendicular}{Hypotenuse}$

$\sin B =\dfrac{h}{c}$

$\sin B =\dfrac{1}{c}\times \dfrac{2D}{a}$ [Using (i)]

$\sin B =\dfrac{2D}{ac}$

$m\angle B =\sin ^{-1}\dfrac{2D}{ac}$ ...(ii)

We have,

$m\angle B=\sin ^{-1}(\dfrac{m}{n})$ ...(iii)

On comparing (ii) and (iii), we get

$m=2D$

$n=ac$

Therefore, the required values are $m=2D, n=ac$ .

6 0

3 years ago

Find the arc length for a circle with diameter 10 inches and central angle 60 degrees. Round to the nearest tenth.

UkoKoshka [18]

Answer:

C. 5.2 cm

Step-by-step explanation:

Arc length formula:

$s = \dfrac{n}{360^\circ} 2 \pi r$

where s = arc length

n = central angle of arc

r = radius of circle

diamter = d = 10 cm

r = d/2 = 10 cm/2 = 5 cm

n = 60 deg

$s = \dfrac{n}{360^\circ} 2 \pi r$

$s = \dfrac{60^\circ}{360^\circ} 2 \times 3.14159 \times 5 ~cm$

$s = 5.2~cm$

Answer: 5.2 cm

6 0

3 years ago

A company logo is made up of a square and three identical triangles.

IgorLugansk [536]

Answer:

$the \: area \: of \: the \: logo \: is \: {91cm}^{2}$

Step-by-step explanation:

To determine the area of the logo you have to calculate the area of the triangle and the square that comform it and then add the four areas.

Area of the square.

To calculate the area of the square you have to calculate the square of one of its sides, following the formula:

$a = {a}^{2}$

Where "a" is the length of one of its side.

The side length of the square is a=7cm, so its area will be:

$asquare = {7}^{2} \\ asquare = {49cm}^{2}$

Area of the triangles.

The three triangles are equal, they have a base equal to the side of the square, i.e. with a length of 7cm, and their height is h=4cm.

To calculate the area of one triangle, you have to multiply its base by its height and divide by 2, following the formula:

$a = \frac{b.h}{2} \\ a = \frac{7.4}{2} \\ a = \frac{28}{2} \\ a = {14cm}^{2}$

The area calculated the correspond to one triangle, since all triangles are congruent, you have to multiply the said area by 3 to determine the area of three figures:

$atriangles = 3a \\ atriangles = {42cm}^{2}$