The Greatest Common Factor of 55 and 80 is 5.
Answer:
0.24 > 0.18
Step-by-step explanation:
Given that,
Bob's stack = 0.2m
Cal's stack = 0.24m
Pete's stack = 0.18m
To find?
A number sentence.
<em>A simple sentence is a string/collection of words that contain a subject and a verb whereas a number sentence is a sentence that consist of </em><em>mathematical operation</em><em> like +, -, /, * together with an equality such as =, <, >, and like a sentence it also tell a fact.</em>
<em> </em>So, the number sentence that compares cal's stack of cards to Pete's stack is
<h2>0.24 > 0.18</h2>
<em />
<em />
<em> </em>
Hello there! We are given the following equation and want to simplify it:

First, let's use the Distributive Property:
For this step, we are going to let:
After applying this version of the Distributive Property, we are given the equation:

We're going to use the distributive party again, but a slightly different version that's almost the same as first:
Using this on both terms of the equation changes the equation to:

Now, we just remove the parenthesis and combine like terms

This should be your answer. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The capacity of an Airliner is k = 300 passengers
The sample size n = 320 passengers
The probability the a randomly selected passenger shows up on to the airport

Generally the mean is mathematically represented as
=>
=>
Generally the standard deviation is

=> 
=> 
Applying Normal approximation of binomial distribution
Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

Here 
=>
Now applying continuity correction we have
=> ![P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )](https://tex.z-dn.net/?f=P%28X%20%20%3E300%20%29%20%3D%20%20P%28Z%20%3E%20%20%5Cfrac%7B%5B300.5%5D%20-%20307.2%7D%7B3.50%7D%20%29)
=> 
From the z-table

So
