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Lena [83]
3 years ago
5

Four classmates went bowling. Each paid $2.00 to rent shoes and bowled ​g​ games, paying $3.50 per player for each game. Which e

xpression shows how many dollars they paid in all?
A. 4(2) + 3.5​g
B. 4(3.5) + 2​g
C. 4(2 +3.5)​g
D. 4(2) + 4(3.5​g​)
Mathematics
2 answers:
OleMash [197]3 years ago
6 0

Answer:

The answer is D!

Step-by-step explanation:

When you answer the question you have 4 players who pay $3.5 per player each game the formula would be 4(3.5g). The you have to calculate in the money they paid to rent shoes which is 4x2 or 4(2) so when you combine the equations you get D)4(2)+4(3.5g)!!!

HOPE THIS HELPS!!

Advocard [28]3 years ago
4 0

Answer:

its A

Step-by-step explanation:

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Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

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  • a²b² = 9b² + a²

Multiply by 4 on both sides,

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Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
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Subtracting equations 2 and 1,

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  • 3a² = 32
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Substituting in 2,

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Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
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Answer:

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3 years ago
If possible step by step explanation. thank you!
elixir [45]

Answer:

A

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\frac{(3x^{2} )^\frac{1}{2} }{3^\frac{1}{2} } =3

(3x^2)^\frac{1}{2} = 3^\frac{1}{2} x

Remember that \frac{x^b}{x^c} =x^(b-c)

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Answer:

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