C - b = a
(13*13) - (4*4) = a
169 - 16 = 153(answer)
Answer:
see below
Step-by-step explanation:
Oddly enough, it is the one that with f(x) <em>reflected over the y-axis</em>. All points on the graph are mirrored across that axis (x is changed to -x, y is left alone).
Answer:
Yes, It is possible for two numbers to have a difference of 8, and a sum of 1.
I hope this helps:)
A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
brainly.com/question/15161224
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