There are various ways in which you could do this problem. I'm going to share what I think is one of the faster ways.
Instead of thinking of jumping from (-1,4) TO (2,-2), Consider the horiz. jump separately and the vertical jump separately. From -1 to 2 is 3 units. Three times that is 9 units. Add 9 to -1, obtaining 8. That's the horiz. component of the terminal point.
From 4 to -2 is -6 units. Mult. that by 3. The result is the vert. comp of the terminal point.
Answer:
A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12
Step-by-step explanation:
In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.
3 = -b/2(1)
3 = -b/2
6 = -b
b = -6
Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.
Answer:
2,099/2,100
Step-by-step explanation:
2,100-1=2,099
180/12= 15
1400+15= 1415.00
The rent would be $1415.00 a month the 5th year.
First step is to factor. With a polynomial function in the form ax² + bx + c = f(x), we have to find what factors of term C have a sum of term B.
So with this, we need factors of -90 add up to become -1. Your factors are - 10 and 9.
f(x) = x² + 9x - 10x - 90
Now we group together and pull out GCFs.
f(x) = (x² + 9x) + (10x - 90)
f(x) = x(x² + 9) - 10(x + 9)
f(x) = (x - 10)(x + 9)
Now, set each factor equal to zero.
x - 10 = 0, x + 9 = 0
For the first equation you are going to add 10 to both sides to get x by itself. Subtract 9 from both sides in the second equation for the same reason.
x = 10, x = -9
Your zeros are at x = -9, 10 or at the ordered pairs (-9, 0) and (10, 0).
