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Gre4nikov [31]
3 years ago
14

Determine the intercepts of the line y= -2x - 21

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

Answer:

what's there to intercept its 1 line

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= -30a^5b + 12a^4b^3 + 6a^3b^2 + 10a^3b^2 - 4a^2b^4 - 2ab^3
= -30a^5b + 12a^4b^3 + 16a^3b^2 - 4a^2b^4 - 2ab^3

answer
B.  -30a^5b + 12a^4b^3 + 16a^3b^2 - 4a^2b^4 - 2ab^3
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8 0
3 years ago
a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect
PolarNik [594]

Number of dimes were 81 and number of quarters were 47

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

<em><u>Given that There are 128 coins in all</u></em>

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

<em><u>Also given that collection of dimes and quarters is worth $19.85</u></em>

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

d \times 0.10 + q \times 0.25 = 19.85

0.1d + 0.25q = 19.85  -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

d = 128 - q -------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

<h3>q = 47</h3>

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

<h3>d = 81</h3>

Thus number of dimes were 81 and number of quarters were 47

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3 years ago
Help with geometry will mark brainliest for correct anwsers
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The first one is (-2,1)
The other one is 36
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