All categories

3 years ago

(-3, 11) a solution to the systems of equations: x – 3y = -36 and 3x + 4y = 48 true or false

Mathematics

2 answers:

Cloud [144]3 years ago

3 0

Answer:

TRUE and FALSE (please look at step-by-step)

Step-by-step explanation:

How to know if it's true or false, you just simply plug in the given numbers to the x and y values.

x = -3

y = 11

for the x - 3y = -36 equation:

-3 -3(11) = -36

-3 - 33 = -36

This equation is true.

for the 3x + 4y = 48 equation:

3(-3) + 4(11) = 48

-9 + 44 = 35

This equation is false.

Nutka1998 [239]3 years ago

3 0

This equation is false

You might be interested in

Please answer quickly:

julia-pushkina [17]

You need to have variables one one side and constants on the other. ax - ax + by = c - ax by = c - ax by/b = (c - ax)/b y = (c - ax)/b

8 0

2 years ago

Read 2 more answers

Simplify 7.675362 please

slega [8]

7.675362
7.67536
7.6754
7.675
7.68
7.7

6 0

3 years ago

Don't get any of this

Serga [27]

Answer:

the value of the printer is going down over the years because it is getting older. all you need to do for this is label the x and y axis with the nbers on the graph and then fill it in

has ur teacher gone over how to fill in graphs yet?

5 0

2 years ago

Read 2 more answers

The ratio of boys to girls is 5:3 there are 80 more boys than girls how many girls are there

shtirl [24]

Answer: 120

Step-by-step explanation:

Ratio Quantity

Boys: 5 80 + x

Girls: 3 x

$\dfrac{5}{3}=\dfrac{80+x}{x}\\\\\\5x=3(80+x)\\\\5x=240+3x\\\\2x=240\\\\x=120$

5 0

2 years ago

Solve question 3 for 41 points

Sever21 [200]

Answer:

(2)

Step-by-step explanation:

Our logarithmic expression is: $ln(\frac{\sqrt{e} }{y^3} )$ .

Remember the logarithmic property that ln(a/b) = lna - lnb. So, we can write this as:

$ln(\frac{\sqrt{e} }{y^3} )=ln(\sqrt{e} )-ln(y^3)$

Also, we can write square roots as powers of one-half, so √e = $e^{1/2}$ . There's another log property that: $ln(a^b)=b*ln(a)$ . We can apply that here for both the √e and the y³:

$ln(\sqrt{e} )-ln(y^3)=\frac{1}{2} ln(e)-3ln(y)$

Finally, note that ln(e) is just 1, so we have:

$\frac{1}{2} ln(e)-3ln(y)=\frac{1}{2} -3ln(y)=\frac{1-6ln(y)}{2}$

The answer is thus (2).

~ an aesthetics lover

7 0

3 years ago