Answer:
x = 13
Step-by-step explanation:
The area (A) of a trapezium is calculated as
A =
h (b₁ + b₂ )
where h is the perpendicular height and b₁, b₂ the parallel bases
Here A = 55, h = 5. b₁ = x, b₂ = 9, then
× 5 × (x + 9) = 55
2.5(x + 9) = 55 ( divide both sides by 2.5 )
x + 9 = 22 ( subtract 9 from both sides )
x = 13
For this, we will divide 1,270,224 by 144.
1,270,224 ÷ 144 = 8,821.
For this result, we can conclude that the number of boxes required to pack 1,270,224 litchis is 8,821 boxes.
Consider the top half of a sphere centered at the origin with radius

, which can be described by the equation

and consider a plane

with

. Call the region between the two surfaces

. The volume of

is given by the triple integral

Converting to polar coordinates will help make this computation easier. Set

Now, the volume can be computed with the integral

You should get