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3 years ago

What is the measure of angle 1?

Mathematics

2 answers:

OleMash [197]3 years ago

5 0

Angle 1 is 123 degrees because it is parallel to the same angle

Sonbull [250]3 years ago

4 0

Answer:

angle 1 = 123°

Step-by-step explanation:

Here, angle 2 = 123° {being veritical opoosite angle}

so, angle 1 = angle 2 {being alternate angle}

so, angle 1 = 123°

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What is the perimeter of a rectangle whose vertices are (2,7) (8,7) (211) (8,11)?

RoseWind [281]

Answer:

e) 20

Step-by-step explanation:

Segment lengths:

|(2, 7) -> (8, 7)| = |(8-2, 7-7)| = |(6, 0)| = 6

|(8, 7) -? (8, 11)| = |(8-8, 11-7)| = |(0, 4)| = 4

because we know it's a rectangle, we can infer that the other two sides also have lengths 4 and 6, so the perimeter is 4+4+6+6=20

5 0

2 years ago

What is the slope of the line that passes through the points (0,-10) and (-4,-11)? Write your answer in simplest form.

Luda [366]

From formula m= y2-y1 / x2-x1

Solution

-11-(-10) /. -4-0

= -1/-4

Have a nice day

8 0

2 years ago

Is 1.999 an irrational number

Roman55 [17]

Yes 1.999 is an <span>irrational number</span>

6 0

2 years ago

Find the value of x

Ahat [919]

recall that a circle has a total of 360°.

so that missing central angle is then 360° - 110° - 65° - 90°. Well, the arc's angle measurement is the same as the central angle they're in, so the x° is the same as 360° - 110° - 65° - 90°.

4 0

2 years ago

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

3 years ago