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lisabon 2012 [21]
3 years ago
9

The table below shows an inequality and a number by which to divide both sides.

Mathematics
2 answers:
IRISSAK [1]3 years ago
6 0

Answer:

i dont see a table

Step-by-step explanation:

Murljashka [212]3 years ago
4 0
I need a table to help you solve this
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Hello! Please help thanks
kogti [31]

Answer:

A. \frac{5}{13}

Step-by-step explanation:

Hi there!

We are given right triangle PQR, with PR=5, RQ=12, and PQ=13

We want to find the value of sin(Q)

Let's first recall that sine is \frac{opposite}{hypotenuse}

In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse

So that means that sin(Q) would be \frac{PR}{PQ}

Substituting the values of PR and PQ gives sin(Q) as \frac{5}{13}, which is A

Hope this helps!

6 0
3 years ago
A motorcycle daredevil is planning a stunt to perform at a county fair. A ramp must be built to give him a 20%
Shkiper50 [21]

Answer: 95 feet

Step-by-step explanation:

Let the length of the horizontal run be represented by x.

Slope Grade = (Rise/Run) × 100

20 = (19/x) × 100

20 = 1900/x

20x = 1900

x = 1900/20

x = 95

Therefore, the length of the horizontal run must be 95 feet

5 0
3 years ago
the radius of the center circle of a basketball court is 6 feet. What is the circumference of the center circle.
Elena-2011 [213]
Remember the equation to find the circumference?

Equation of circumference: Pi x 2(radius)

Therefore, 3.141592654 x 2(6ft) = 37.7 feet
6 0
3 years ago
Read 2 more answers
Ingrid bought a laptop that was 30% off the regular price of $1,050. If a 7% sales tax was added to the cost of the laptop, what
melamori03 [73]
Her total price would be $786.45
5 0
3 years ago
The Town of Hertfordshire clerk knows that 23% of dogs in the town have completed emotional support training. Hertfordshire plan
Nataly_w [17]

Answer:

95.64% probability that under 30% of the dogs are emotional support trained

Step-by-step explanation:

For each dog, there are only two possible outcomes. Either they have completed emotional support training, or they have not. So we use the binomial probability distribution to solve this problem.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

\mu = E(X) = np = 100*0.23 = 23

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.23*0.77} = 4.21

What is the probability that under 30% of the dogs are emotional support trained?

30% of 100 is 0.3*100 = 30

So this is the pvalue of Z when X = 30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 23}{4.1}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564.

So there is a 95.64% probability that under 30% of the dogs are emotional support trained

5 0
3 years ago
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