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kodGreya [7K]
3 years ago
7

Please help it’s for geometry

Mathematics
2 answers:
Troyanec [42]3 years ago
6 0

Answer:

BI=BK

Step-by-step explanation:

BJ=BJ(common side)

<BJI=<BJK=90° (Perpendicular given)

IJ=JK (Bisector given)

congruent triangle ∆BIJ=~∆BKJ (RHS rule)

therefore, BI= BK

Bad White [126]3 years ago
5 0
I cannot see the whole question
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Rearrange the formula to solve for current assets (CA).
Aleksandr [31]

<em>Answer:</em>

<em>the formula is Current assets = Cash and Cash Equivalents + Accounts Receivable + Inventory + Marketable Securities + Prepaid Expenses.</em>

<em>Step-by-step explanation:</em>

<em>Current assets typically include categories such as cash, marketable securities, short-term investments, accounts receivable , prepaid expenses, and inventory.</em>

7 0
3 years ago
Y+1=3(x – 4)<br> 2-intercept:<br> C<br> y-intercept:
kiruha [24]

Answer:

x-intercept is (13/3, 0)  

y-intercept is (0,-13)

Step-by-step explanation:

change y+1 = 3(x-4) into slope-intercept form:

y+1 = 3x-12

y = 3x-13

y-intercept is (0,-13)

to get x-intercept, plug zero in for 'y' and solve for 'x':

0 = 3x-13

13 = 3x

13/3 = x

x-intercept is (13/3, 0)  

4 0
3 years ago
1. Find the surface area of a square pyramid with a base length of 24 cm and a height of 16 cm. A. 1056 cm2 B. 1536 cm2 C. 816 c
Deffense [45]
We have that

<span>1. Find the surface area of a square pyramid with a base length of 24 cm and a height of 16 cm

[surface area]=[area of 4 triangles sides]+[area of square base]
</span>[area of square base]=24*24--------> 576 cm²

[area of one triangles side]
l=slant height
l²=16²+12²-------> l²=400-----------> l=20 cm
[area of one triangles side]=24*20/2--------> 240 cm²
[area of 4 triangles sides]=4*240----------> 960 cm²
[surface area]=[960]+[576]--------> 1536 cm²

the answer part 1) is option B) 1536 cm²

<span>2. Use 3.14 for π and round to the nearest tenth.
</span>Find the surface area of the cylinder<span>
radius=8 in
<span>height= 8 in
</span></span>[surface area]=2*[area of circular base]+[Perimeter of base]*h
[area of circular base]=pi*8²----> 200.96 in²
Perimeter=2*pi*8--------> 50.24 in
[surface area]=2*[200.96]+[50.24]*8-----------> 803.84 in²

the answer Part 2) is the option C) 803.8 in²

<span>3. Find the volume of the cylinder.
</span>[volume of the cylinder]=[area of circular base]*h
[volume of the cylinder]=[200.96]*8---------> 1607.68 in³

the answer Part 3) is the option A.) 1607.7 in.3

<span>4.Find the volume of a rectangular prism with the following dimensions:
Length = 5 mm
Base = 7 mm
Height = 3 mm
</span>
[volume of a rectangular prism]=L*B*H

[volume of a rectangular prism]=5*7*3----------> 105 mm³

the answer part 4) is the option <span>B.) 105 mm3

</span><span>5.Find the volume of the given pyramid.
A large pyramid has a height of 7 yards, radius of 9 yards, and base of 7 yards.
</span>this question is incorrect

the correct question is
5a) A large pyramid has a height of 7 yards and radius of 9 yards. (pyramid with circular base)
or 
5b) A large pyramid has a height of 7 yards and base of 7 yards. (pyramid with square base)

<span>we will solve the two cases
</span>
5a) A large pyramid has a height of 7 yards and radius of 9 yards. (pyramid with circular base)
[volume of the pyramid]=pi*r²*h/3---------> pi*9²*7/3---------> 593.46 yd³

the answer Part 5a) is 593.46 yd³



5b) A large pyramid has a height of 7 yards and base of 7 yards. (pyramid with square base)

[volume of the pyramid]=b²*h/3---------> 7²*7/3---------> 114.33 yd³

the answer Part 5b) is 114.33 yd³


<span>6.Find the volume of a square pyramid with a base length of 9 cm and a height of 4 cm.

[</span>volume of a square pyramid]=b²*h/3---------> 9²*4/3-------> 108 cm³

the answer Part 6) is the option <span>B.)1</span>08 cm³
4 0
3 years ago
The temperature of the water in Emily's fish tank was 78 on Sunday the water temperature changed by -3 on Monday and then 3 on T
Scilla [17]

Answer:

change was 0

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Step-by-step explanation:

8 0
3 years ago
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saw5 [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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