Answer:
Perimeter of Δ XYZ = 24.13
Step-by-step explanation:
In Δ XYZ is a right triangle because the XYZL is a square. Therefore the hypotenuse = 10; Looking at the 43° angle, XY is the side that is opposite the 43° angle and the YZ is the side that is adjacent to the 43°.
Using the trig ratios:
XY = opposite/ hypotenuse which is Sin 43°
Sin 43° = XY/ 10
10(Sin 43°) = XY
6.82 = XY
YZ = adjacent/hypotenuse which is Cos 43°
Cos 43° = YZ/10
10(cos 43°) = YZ
7.31 = YZ
Now the Perimeter = XY + YZ + XZ
Perimeter = 6.82 + 7.31 + 10
Perimeter = 24.13
I already answered this somewhere. Search the problem.
It is 126 x=67 I hope this helps
there are only 3 tangent lines can be drawn that touch both circles
ok done. Thank to me :>
x=3
Step-by-step explanation:
x+2=5
x=5-2
x=3
