Let P(n) be "a postage of n cents can be formed using 5-cent and 17-cent stamps if n is greater than 63".Basis step: P(64) is true since 64 cents postage can be formed with one 5-cent and one 17-cent stamp.Inductive step: Assume that P(n) is true, that is, postage of n cents can be formed using 5-cent and 17-cent stamps. We will show how to form postage of n + 1 cents. By the inductive hypothesis postage of n cents can be formed using 5-cent and 17-cent stamps. If this included a 17-cent stamp, replace this 17-cent stamp with two 5-cent stamps to obtain n + 1 cents postage. Otherwise, only 5-cent stamps were used and n 65. Hence there are at least three 5-cent stamps forming n cents. Remove three of these 5-cent stamps and replace them with two 17-cent stamps to obtain n + 1 cents postage.Hence P(n + 1) is true.
Answer:
import re
def country_capita():
#opens file
file=open("inputfile.txt", "r")
dictionary=dict()
#reads line by line
for line in file.readlines():
# substitutes for multiple space a single space
line = re.sub(r"[\s]{2, }", ' ', line)
list=[]
#splits line on space
list=line.split(" ")
#put into dictionary
dictionary[list[1]]=list[2]
# get input
while True:
choice=input("Enter the country name or quit to exit: ")
if choice=="quit":
break
elif choice in dictionary.keys():
print(dictionary[choice])
else:
print("Invalid Country")
country_capita()
Explanation:
Using python to code this program. First we, (line 1) import the re module which offers us a set of functions that allows us to search a string for a match. ((line 2) Next we define a function country_capita() that will open rawdata_2004.txt, read the information within line by line and create a dictionary list. The we create a while loop with conditional statements that prompt the user to enter country names, print the corresponding values and stops when the user enters quit.
Each lab consists of a PreLab, InLab, and a PostLab. PreLabs are worth 20%, InLab 50%, and PostLabs 30% of the final lab grade. the fifth submission is worth 40%.
<h3>
What is prelab?</h3>
- Pre-lab assignments are tasks or homework that students complete before arriving in class for the lab period.
- Pre-lab assignments motivate students to prepare for the lab and help them connect conceptual understanding with an experiment.
<h3>What is inlab?</h3>
- With inLab CAD Software, you design digital dentures and partial frameworks as well as splints, impression trays, and telescopes.
<h3>What is postlab?</h3>
- Postlab is a Mac app that lets you collaborate on Final Cut Pro X libraries and Premiere Pro projects.
- Postlab enables editors to share files, track and save changes, and make sure no more than one person is working on the same library or project simultaneously.
To learn more about it, refer
to brainly.com/question/22654163
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A cloud service providers uses KVM in their data centers because they are gravely concerned with insider threats.
KVM is a system for management, monitoring and control of a data center environment from a central location. In the data center this system is very necessary because the data center has multiple servers and computers. With this system the server can be connected and controlled from a remote location. This includes mapping the physical locations of accessible virtual drives.
Your question is incomplete, but most probably you full question was:
Modern managed cloud service providers will often use secure Keyboard/Video/Mouse (KVM) devices within their data centers. these devices are extremely expensive compared to their non-secured counterparts. which of the following is one of the reasons cloud service providers do this?
- They have plenty of revenue and can afford it
- They are gravely concerned with insider threats
- Cloud data centers need very few of these devices
- Managed cloud providers often manufacture their own devices as well
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Answer:
1 PROCESSOR :
(1 × 2.56 × 10^9) + (12 × 1.28 × 10^9) + (5 × 2.56 × 10^8) / 2 GHz = 9.6 s
2 PROCESSORS :
(1×2.56×10^9)+(12×1.28×10^9)/0.7×2 + (5 × 2.56 × 10^8) / 2 GHz = 7.04 s
Speed -up is 1.36
4 PROCESSORS :
(1×2.56×10^9)+(12×1.28×10^9)/0.7×4 + (5 × 2.56 × 10^8) / 2 GHz = 3.84 s
Speed -up is 2.5
5 PROCESSORS :
(1×2.56×10^9)+(12×1.28×10^9)/0.7×8 + (5 × 2.56 × 10^8) / 2 GHz = 2.24 s
Speed -up is 4.29
Explanation:
The following formula is used in this answer:
EXECUTION TIME = CLOCK CYCLES / CLOCK RATE
Execution Time is equal to the clock cycle per clock rate
