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2 years ago

Make non proportional equation for the tables

Mathematics

1 answer:

TEA [102]2 years ago

4 0

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Please help its a quiz Click this is with picture

Bogdan [553]

Answer:

-16

Step-by-step explanation:

Subtract the afternoon temperature from the evening temperature

3 0

2 years ago

Read 2 more answers

WIll give brainliest Use the information given to answer the question.

MaRussiya [10]

Answer:

x²-12x+36

Step-by-step explanation:

an expression in the form (a-b)² is expanded to the form a²-2ab+b²

you can also expand it to (x-6)×(x-6) then multiply the first term by the first the outer term by the outer term the inner term by the inner term and the last term by the last term (foil)

the first terms are x and x = x² the outer terms are x and -6 = -6x the inner terms are also x and -6 = -6x

the last terms are 6 and 6 = 36

adding all the four products =

x²-12x+36

7 0

2 years ago

Given: ΔABC, m∠C = 90º, m∠B = 30º CM - angle bisector Find: m∠AMC

SashulF [63]

Answer:

75°

Step-by-step explanation:

1. Consider right triangle ABC. In this triangle

m∠C = 90º and CM - angle bisector.

If CM is angle C bisector, then

m∠ACM = m∠MCB = 45º

2. Consider triangle CMB. The sum of the measures of all interior angles of the triangle is always 180°, then

m∠MCB + m∠CBM + m∠BMC = 180°,

m∠BMC = 180° - 45° - 30°

m∠BMC = 105°

3. Angles AMC and BMC are supplementary angles, so

m∠AMC + m∠BMC = 180°

m∠AMC = 180° - 105°

m∠AMC = 75°

3 0

2 years ago

Please solve this question!!

GaryK [48]

Answer: (i) 1/221 (ii) 11/221 (iii) 95/663 (iv) 1/663

Step-by-step explanation:

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards → 3/51 = 1/17

1st Draw 2nd Draw Outcome Probability

King: P(K) = 1/13 King: P(K₂/K₁) = 1/17 King, King (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards → 11/51

1st Draw 2nd Draw Outcome Probability

Face: P(F) = 3/13 Face: P(F₂/F₁) = 11/51 Face,Face (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards → 19/51

1st Draw 2nd Draw Outcome Probability

Black: P(B~) = 5/13 Black: P(B~₂/B~₁) = 19/51 B~,B~ (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards → 1/51

1st Draw 2nd Draw Outcome Probability

Ace: P(A) = 1/13 Qh: P(Qh₂/A₁) = 1/51 Ace,Queen(h) (1/13) x (1/51) = 1/663

7 0

3 years ago

A truck weighing 150kN and travelling at 2m/sec impacts with a buffer

FrozenT [24]

The maximum compression of the spring is 0.276 m

Step-by-step explanation:

First of all, we calculate the spring constant of the spring, by using Hooke's law:

$F=kx$

where

F = 10 kN = 10,000 N is the force applied

x = 1.25 cm = 0.0125 m is the corresponding compression of the spring

k is the spring constant

Solving for k,

$k=\frac{F}{x}=\frac{10,000}{0.0125}=8\cdot 10^5 N/m$

When the truck impacts with the spring, all the kinetic energy of the truck is converted into elastic potential energy of the spring, so we can write

$\frac{1}{2}mv^2=\frac{1}{2}kx^2$ (1)

where

m is the mass of the truck

v = 2 m/s is the initial speed of the truck

$k=8\cdot 10^5 N/m$ is the spring constant

x is the compression of the spring

The mass of the truck can be found from its weight:

$m=\frac{W}{g}=\frac{150,000 N}{9.81 N/kg}=15,290 kg$

So now we can re-arrange eq.(1) to find the compression, x:

$x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(15,290)(2)^2}{8\cdot 10^5}}=0.276 m$

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

6 0

3 years ago