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Setler79 [48]
3 years ago
6

Aurora has a cell phone plan that charges $65 for phone service plus $12 for each gigabyte of data used each month. If her bill

for September is $113,how many gigabytes of data did she use in September?
Mathematics
2 answers:
kondaur [170]3 years ago
4 0

Answer:

She used 4 gigabytes of data in September.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • <em>Phone service plan: $65 </em>
  • <em>Cost per gigabyte: $12 </em>
  • <em>Bill: $113 </em>

So, to find the number of gigabytes that she used we have to write an equation:

65 + 12x = 113

Where:

x = number of gigabytes

Solving for x

12x = 113-65

12x =48

x = 48/12

x =4

She used 4 gigabytes of data in September.

MatroZZZ [7]3 years ago
3 0

Answer:

The answer is 4 gigabytes of data were used

If you take 65 and add 12 to it 4 times you get 113 so the answer is 4.

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3 years ago
Help! Urgent request
TiliK225 [7]

Answer: 6 students

What we know:

Students: 24

Students who play checkers: \frac{2}{3}

Students who also play sudoku:\frac{3}{8} of the \frac{2}{3}

24 ÷ 3 = 8, so 8 × 2 = 16 (students who play checkers)

\frac{3}{8} × 2 = \frac{6}{16}

So the answer is,

6 students play both checkers and sudoku

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3 years ago
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9.75 dollars divided by 3 pounds equals 3.25 per pound
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4 years ago
12x⁴y²divided by 3x³y to the 5 th power....Please help me out....
ki77a [65]
To divide the expression we proceed as follows:
12x⁴y²÷3x³y⁵
=12x⁴y²/3x³y⁵
=(12÷3)×(x⁴÷x³)×(y²÷y⁵)
when you divide number with the same base, you subtract the numerators:
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5 0
3 years ago
1. Writing an equation for an exponential function by
Naya [18.7K]

Answer: 1) t(n)=0.6(2)^n

2) f(x)=10(5)^x

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

t(n) = ab^n         ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

By equation (1),

0.6 = a(b)^0\implies 0.6 = a

Hence the function that shows the given situation,

t(n) = 0.6 b^n       -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

Thus, at n = 1, t(1) = 1.2

By equation (2),

1.2 = 0.6 b^1\implies 2 = b

Thus, the complete function is,

t(n) = 0.6 (2)^n    

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = ab^x         ---------(1)

For f(x) = 2, x = -1

By equation (1),

2= ab^{-1}       ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

\frac{2}{5}= a(b)^{-2}

\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}

\implies \frac{2}{5}=\frac{2}{b}

\implies 2b=10

\implies b = 5

By substituting this value in equation (2),

We get, a = 10

Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = 10(5)^x

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3 years ago
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