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drek231 [11]
3 years ago
11

The height and the base area b of a cone are given fine the volume of the cone h=6units b=4 pie square units ?

Mathematics
1 answer:
aev [14]3 years ago
4 0

Answer:

24 may be

Step-by-step explanation:

coz i dont kmow waiii i dont know

m soo sry to disturb u

may god find ur answer

god bless u

be happy alys

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What is the value of the expression -2^2+4x(-3) when x= -3
Kisachek [45]
It will be
(-2)^2+4*(-3)(-3) =40
6 0
3 years ago
The number of transistors per IC in 1972 seems to be about 4,000 (a rough estimate by eye). Using this estimate and Moore's Law,
spayn [35]

Answer:

The prediction for the number of transistor per IC in 1992 is of 4,194,304,000

Step-by-step explanation:

Moore's law:

Moore's law states that the number of transistors per IC doubles every year.

Format of the function:

Following Moore's law, t years after our initial estimative, the number of transistors per IC will be given by:

N(t) = N(0)*2^t

In which N(0) is the initial estimate.

The number of transistors per IC in 1972 seems to be about 4,000 (a rough estimate by eye).

This means that N(0) = 4000

So

N(t) = 4000*2^t

What would you predict the number of transistors per IC to be 20 years later, in 1992?

This is N(20). So

N(20) = 4000*2^20 = 4194304000

The prediction for the number of transistor per IC in 1992 is of 4,194,304,000

4 0
3 years ago
The temperature in Armand’s town in the morning was – 3.6°F. The temperature in the afternoon was 0°F. What was the overall chan
OLEGan [10]

The overall temperature would be 3.6°F as this is how much it was changed by

Answer=3.6°F

7 0
3 years ago
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What is 87/96 feet in inches
wariber [46]
10.875 inches would be your answer
6 0
3 years ago
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Pls help asap whats the local min value of the function below?
shutvik [7]

Answer:

<em>given function has 2 minimums</em> - \frac{9}{4}  and  \frac{9}{4}  

Step-by-step explanation:

<u><em>Step 1.</em></u> g'(x) = 4x³ - 10x

<u><em>Step 2.</em></u> Find find the critical points:

4x³ - 10x = 2x(2x² - 5) = 0

x_{1} = - \sqrt{\frac{5}{2} } , x_{2} = 0 , x_{3} = \sqrt{\frac{5}{2} }

<u><em>Step 3.</em></u> g'(x) > 0 :  - \sqrt{\frac{5}{2} } < x < 0  or  x > \sqrt{\frac{5}{2} }

g'(x) < 0 :   x < - \sqrt{\frac{5}{2} }   or   0 < x < \sqrt{\frac{5}{2} }

<u><em>Step 4.</em></u>

If x ∈ ( - ∞ , - \sqrt{\frac{5}{2} } ) , g(x) is decreasing ;

If x = - \sqrt{\frac{5}{2} } , g(x) has <em>minimum</em> value ;

If x ∈ ( - \sqrt{\frac{5}{2} } , 0 ) , g(x) is increasing ;

If x = 0 , g(x) has maximum value ;

If x ∈ ( 0 , \sqrt{\frac{5}{2} } ) , g(x) is decreasing ;

If x = \sqrt{\frac{5}{2} } , g(x) has <em>minimum</em> value ;

If x ∈ ( \sqrt{\frac{5}{2} } , ∞ ) , g(x) is increasing .

⇒ at ( - \sqrt{\frac{5}{2} } , - \frac{9}{4} ) and at ( \sqrt{\frac{5}{2} } , \frac{9}{4} ) , g(x) reaches its minimum

8 0
3 years ago
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